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Class 11 Statistics Questions asked by Filo students

Question 81

Views: 5,298

Texts: To test Hg=100 versus H100, a simple random sample size of n=21 is obtained from a population that is known to be normally distributed. Answer parts a-d.

If X=105.4 and s=9.2, compute the test statistic t. Round to three decimal places as needed.
If the researcher decides to test this hypothesis at the 0.01 level of significance, determine the critical values. The critical values are (Use a comma to separate answers as needed). Round to three decimal places as needed.
Draw a t-distribution that depicts the critical region(s). Which of the following graphs shows the critical regions in the t-distribution? O A O B O C O D
Will the researcher reject the null hypothesis?

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Question 82

Views: 5,130

Texts: A golf association requires that golf balls have a diameter that is 1.68 inches. To determine if golf balls conform to the standard, a random sample of golf balls was selected. Their diameters are shown in the accompanying data table. Do the golf balls conform to the standards? Use the α = 0.01 level of significance. Click the icon to view the data table X Data Table First, determine the appropriate hypotheses: Ho: The mean diameter of the golf balls is equal to 1.68 inches. H1: The mean diameter of the golf balls is not equal to 1.68 inches. 1.683 1.686 1.684 1.685 1.676 1.677 1.685 1.682 1.682 1.685 1.673 1.674 (Type integers or decimals. Do not round.) Find the test statistic. (Round to two decimal places as needed.) Find the P-value. Print Done (Round to three decimal places as needed.) What can be concluded from the hypothesis test?

Reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance.
Do not reject Ho. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance.
Reject H1. There is sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance.
Do not reject Ho. There is not sufficient evidence to conclude that the golf balls do not conform to the association's standards at the α = 0.01 level of significance.

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Question 83

Views: 5,466

.06 .10 .14 .18 .22 .26 .30mean is 18% standard deviation is 4%What is the probability of randomly choosing a county where 12.5% of the population is 65 and older? Show what you put in your calculator. Round your answer to four decimal places. Write a sentence explaining what your answer represents in the context of this problem.Calculate the z-score for a county with 13% of its population that is 65 and older. Write a sentence stating specifically what this z-score represents in the context of this problem. Write your answer to 2 decimal places. u= 0 J I - - - I -

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Question 84

Views: 5,870

Text: An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2: Suppose a sample of 1453 tankers is drawn. Of these ships, 989 did not have spills. Using the data, construct the 99% confidence interval for the population proportion of oil tankers that have spills each month. Round your answers to three decimal places.

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Question 85

Views: 5,275

Which one of Cook and Campbell's (1979) four big validities best addresses whether the sample was of sufficient size?

External
Internal
Construct
Statistical

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Question 86

Views: 5,180

Texts: (1 point) The Census Bureau reports that 82% of Americans over the age of 25 are high school graduates. A group of 108 randomly selected Americans over the age of 25 were surveyed. Use the normal approximation to the binomial distribution to find the following: (Round all decimals to at least 3 places) a) What is the probability that 80 of the residents who were surveyed were high school graduates? 0.0155 b) What is the probability that at most 54 of the residents who were surveyed were high school graduates? 0.191

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Question 87

Views: 5,344

Texts: The accompanying tree diagram represents an experiment consisting of two trials. E Use the diagram to find the probabilities below:

P(A) = 0.9
P(EA) = 0.4
P(A ∩ E) = 0.12
P(¬A) = 0.18

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Question 88

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Question 6 of 27 Step 1 of 2 Customer account numbers for a certain company consist of 3 letters followed by 3 numbers. Step 1 of 2: How many different account numbers are possible if repetitions of letters and digits are allowed?

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Question 89

Views: 5,215

Identify the following as either a parameter or a statistic, and give the correct notation. Average commute time for employees at a small company, based on interviews with a few employees. Parameter: μ (mu) Statistic: x̄ (x-bar)

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Question 90

Views: 5,451

Which of the following data types describes sequential values, where the distance between values is not meaningful?

Ratio
Ordinal
Nominal
Interval

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Question 91

Views: 5,940

Soru 6 Suppose that the random variable Z has a standard normal distribution. Find the following probabilities: P(Z < 1.58) = P(Z < -2.55) = P(Z > -0.55) = P(Z > 1.91) = P(Z = 2.1) =

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Question 92

Views: 5,372

Texts: In a recent survey, 45 percent indicated chocolate was their favorite flavor of ice cream. Suppose we select a sample of 8 people and ask them to name their favorite flavor of ice cream. a. How many of those in the sample would you expect to name chocolate? (Round your answer to the nearest whole number.) Expected number of people. b. What is the probability exactly five of those in the sample name chocolate? (Round the probability to 5 decimal places and the final answer to 4 decimal places.) Probability. c. What is the probability five or more name chocolate? (Round your probability to 4 decimal places.)

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Question 93

Views: 5,719

The probability that you will win a game is π = 0.49. If you play the game 514 times, what is the most likely number of wins? (Round answer to one decimal place.) Let X represent the number of games (out of 514) that you win. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) The range rule of thumb specifies that the minimum usual value for a random variable is μ - 20 and the maximum usual value is μ + 20. You already found μ and σ for the random variable X. Use the range rule of thumb to find the usual range of X values. Enter answer as an interval using square brackets and only whole numbers. Usual values.

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Question 94

Views: 5,318

Texts: 17.[-/2.96 Points] DETAILS BBUNDERSTAT 136.3.038.S MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The amount of money spent weekly on cleaning =

635 an d s t an d a r dd e v ia t i o n =

44 over a long period of time to be approximately normally distributed, with mean USE SALT a1f 5641 is budgeted for next week. What is the probability that the actual costs will exceed your answer to four decimal places? Y 19 b How much should be budgeted for weekly repairs in dollars? Round your answer to the nearest dollar. Need Help

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Question 95

Views: 5,299

Texts: evaluated. The mean sodium level for the sample is 141 mEq per liter of blood. It's known that the population standard deviation of adult sodium levels is 13 mEq. Assume that the population is normally distributed. Can we conclude, at the 0.01 level of significance, that the population mean adult sodium level differs from that given in the textbook? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places, and round your responses as specified below. If necessary, consult a list of formulas. a) State the null hypothesis (H0) and the alternative hypothesis (Ha). H0: The population mean adult sodium level is equal to that given in the textbook. Ha: The population mean adult sodium level differs from that given in the textbook. b) Determine the type of test statistic to use. Choose one: - Z-test - T-test c) Find the value of the test statistic. (Round to three or more decimal places.) a = C < O d) Find the p-value. (Round to three or more decimal places.) 5 e) Can we conclude that the population mean adult sodium level differs from that given in the textbook? - Yes - No

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Question 96

Views: 5,467

Texts: shown below 0.6 02 08 02 050503 0.4 Would you agree with the claim? Assume a normal distribution. Check page 1 for more information. Check page 2 for the state of citation. The computation is 0.7, so PTs. This provides evidence to disagree with the claim. (Round to two decimal places as needed) A

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Question 97

Views: 5,143

Texts: One personality test available on the World Wide Web has a subsection designed to assess the honesty of the test-taker. You are interested in the mean score among the general population on this subsection. The website reports that μ is 142, but you have good reason to believe that μ is greater than 142. You decide to do a statistical test. You choose a random sample of people and have them take the personality test. You find that their mean score on the subsection is 149 and that the standard deviation of their scores is 25. Based on this information, complete the parts below. a) What are the null hypothesis H0 and the alternative hypothesis that should be used for the test? H0: μ ≤ 142, Ha: μ > 142 b) Suppose that you decide not to reject the null hypothesis. What sort of error might you be making? Type II error Suppose the true mean score among the general population on the subsection is 142. Fill in the blanks to describe a Type I error. A Type I error would be rejecting the hypothesis that μ ≤ 142 when, in fact, μ ≤ 142.

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Question 98

Views: 5,622

Texts: Not too. Happy. Pretty. Happy. Very. Happy. Below 0. 4. 1. 4. 11. 1. Average. Above 0. 12. 8. The table has 204 concordant pairs and 55 discordant pairs. Show these are true numbers.

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Question 99

Views: 5,122

Text: A recent survey asked 1719 people how many hours per day they were able to relax. The results are presented in the following table: Frequency: 0 - 119: 192 2 - 325: 3 262: 4 322: 240 146: 44 8: 69 Total: 1719

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Question 100

Views: 5,818

I am stuck on these questions, please help! Kiss example with two observations 0/2 points (graded) Consider the (somewhat extreme case) of the Kiss example where we collect only two observations R and R that are i.i.d Ber (). We still denote by R their average with the understanding that = 2. We still want to test Ho:p=.5 HP.5 at level 5%. The goal of this exercise is to investigate the limits of Walds test and propose a potential remedy. 1) How many values can R, take? 2) Consider using the Wald test at asymptotic level = 5% for this test. Assuming that the null hypothesis is true, what is the actual probability of type 1 error for this test? STANDARD NOTATION Submit You have used 1 of 10 attempts Save X Incorrect (0/2 points) Kiss example with two distinct observations 3 points possible (graded) In this problem we use the same setup as the previous question. For the next three questions, assume that the two observations R1 and R are different. 1) What is the asymptotic p-value of the Wald test (apply directly the formula from the slides). 2) What is the actual p-value of the Wald test P.s (|W> [Wobs 3) What is the conclusion of the Wald test at asymptotic level 5%? Reject Fail to reject

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