Chapter Analytic Geometry, Question Problem 17AYU

If the major axis of the parabola is parallel to the y-axis then it is in the form of $k(y-a)=(x-b{)}^2$, where $(b,a)$ is the vertex of the parabola and $k$ is a constant (positive if open up, negative if open down). If the major axis of the parabola is parallel to the x-axis then it is in the form of $k(x-a)=(y-b{)}^2$, where $(a,b)$ is the vertex of the parabola and $k$ is a constant. (positive if open right, negative if open left) Here the major axis is parallel to the x-axis, $k=\pm 4$ in all cases, but here it is open down, hence $k=-4$ and the vertex is in $(-1,-1)$. Hence the equation: $$\begin{gathered} -4(y-(-1))=(x-(-1){)}^2 \\ -4(y+1)=(x+1{)}^2 \end{gathered}$$ Thus the answer is h).