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At very low pressure, what is the equation of Langmuir Adsorpt

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At very low pressure, what is the equation of Langmuir Adsorption Isotherm ? a. $\frac{x}{m} = K p^{\frac{1}{n}}$ b. $\frac{x}{m} = \frac{a p}{1 + b p}$ c. $\frac{x}{m} = a p$ d. $\frac{x}{m} = \frac{a}{b}$

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At very low pressure, what is the equation of Langmuir Adsorption Isotherm ? a.

\frac{x}{m} = K p^{\frac{1}{n}}

\frac{x}{m} = \frac{a p}{1 + b p}

\frac{x}{m} = a p

\frac{x}{m} = \frac{a}{b}

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Text solutionVerified

Sure, here are the step by step solutions: Given:

C \frac{x}{m} = a p

To solve for

x

, we will isolate it on one side of the equation. Step 1: Multiply both sides of the equation by

\frac{m}{C}

C \cdot \frac{x}{m} \cdot \frac{m}{C} = a p \cdot \frac{m}{C}

Simplifying, we get:

x = \frac{a p m}{C}

Therefore, the solution for

x

\frac{a p m}{C}

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Question Text	At very low pressure, what is the equation of Langmuir Adsorption Isotherm ? a. $\frac{x}{m} = K p^{\frac{1}{n}}$ b. $\frac{x}{m} = \frac{a p}{1 + b p}$ c. $\frac{x}{m} = a p$ d. $\frac{x}{m} = \frac{a}{b}$
Topic	Surface Chemistry
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1