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Chapter Functions And Their Graphs, Question Problem 14AYU
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Text solutionVerified
The only restriction to the given function is that since the denominator cannot be equal to zero.
The function is defined for both and
Thus, the give statement is false.
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Question Text | Chapter Functions And Their Graphs, Question Problem 14AYU |
Topic | All Topics |
Subject | Algebra 2 |
Class | Class 9 |
Answer Type | Text solution:1 |