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Physics Part-I

Electric Charges and Fields

The electrostatic force on a small sphere of charge 0.4 C due

Physics Part-I

Class 12

NCERT

Chapter 1: Electric Charges and Fields

47 questions

What is the force between two small charged spheres having charges of

2 \times 1 0^{- 7}

C and

3 \times 1 0^{- 7}

C placed 30 cm apart in air?

The electrostatic force on a small sphere of charge

0.4 μ C

due to another small sphere of charge

- 0.8 μ C

in air is 0.2 N.

(a) What is the distance between the two spheres?

(b) What is the force on the second sphere due to the first?

Check that the ratio

k e^{2}

m_{e} m_{p}

is dimensionless. Look up a Table of Physical Constants and detere the value of this ratio. What does the ratio signify?

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Question

Easy

Solving time: 2 mins

The electrostatic force on a small sphere of charge $0.4 μ C$ due to another small sphere of charge $- 0.8 μ C$ in air is 0.2 N.
(a) What is the distance between the two spheres?
(b) What is the force on the second sphere due to the first?

Views: 5,643 students

Updated on: Feb 27, 2024

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Physics Part-I (NCERT)

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The electrostatic force on a small sphere of charge

0.4 μ C

due to another small sphere of charge

- 0.8 μ C

in air is 0.2 N.

(a) What is the distance between the two spheres?

(b) What is the force on the second sphere due to the first?

13 mins ago

Discuss this question LIVE

13 mins ago

Text solutionVerified

(a)

Electrostatic force on the first sphere, $F = 0.2 N$

Charge on this sphere, $q_{1} = 0.4 μ C = 0.4 \times 1 0^{- 6} C$

Charge on the second sphere, $q_{2} = - 0.8 μ C = - 0.8 \times 1 0^{- 6} C$

Electrostatic force between the spheres is given by the relation,

$F = \frac{q _{1} q _{2}}{4 π ε _{0} r ^{2}}$

And, $\frac{1}{4 π ε _{0}} = 9 \times 1 0^{9} N m^{2} C^{- 2}$

Where, $ε_{0} =$ Permittivity of free space

$r^{2} = \frac{q _{1} q _{2}}{4 π ε _{0} F}$

$= \frac{04 \times 1 0 ^{- 6} \times 8 \times 1 0 ^{- 6} \times 9 \times 1 0 ^{9}}{0.2}$

$= 144 \times 1 0^{- 4}$

$r = 144 \times 1 0^{- 4}$

$= 0.12 m$

The distance between the two spheres is 0.12 m.

(b) Equal and Opposite Force acts on the other sphere (By newton's Third Law). Hence 0.2 N attractive.

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Practice more questions from Physics Part-I (NCERT)

What is the force between two small charged spheres having charges of

2 \times 1 0^{- 7}

C and

3 \times 1 0^{- 7}

C placed 30 cm apart in air?

The electrostatic force on a small sphere of charge

0.4 μ C

due to another small sphere of charge

- 0.8 μ C

in air is 0.2 N.

(a) What is the distance between the two spheres?

(b) What is the force on the second sphere due to the first?

Check that the ratio

k e^{2}

m_{e} m_{p}

is dimensionless. Look up a Table of Physical Constants and detere the value of this ratio. What does the ratio signify?

View all

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Question Text	The electrostatic force on a small sphere of charge $0.4 μ C$ due to another small sphere of charge $- 0.8 μ C$ in air is 0.2 N. (a) What is the distance between the two spheres? (b) What is the force on the second sphere due to the first?
Updated On	Feb 27, 2024
Topic	Electric Charges and Fields
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 10
Upvotes	1039
Avg. Video Duration	4 min

The electrostatic force on a small sphere of charge $0.4 μ C$ due to another small sphere of charge $- 0.8 μ C$ in air is 0.2 N.
(a) What is the distance between the two spheres?
(b) What is the force on the second sphere due to the first?

Text solutionVerified

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Text solutionVerified

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The electrostatic force on a small sphere of charge $0.4 μ C$ due to another small sphere of charge $- 0.8 μ C$ in air is 0.2 N.
(a) What is the distance between the two spheres?
(b) What is the force on the second sphere due to the first?