[Solved] A horizontal straight wire 10 m long extending from east to west is falling with a speed of5.0ms–1 , at right angles to the horizontal component of the earth’s magnetic field, 0.30×10–4Wbm–2 . (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential? - Physics Part-I

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Electromagnetic Induction

A horizontal straight wire 10 m long extending from east to we

Physics Part-I

Class 12

NCERT

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A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of in a uniform horizontal magnetic field of magnitude

3.0 \times 1 0^{-2 T}

. Obtain the maximum and average emf induced in the coil. If the coil forms a closed loop of resistance 10 Ω, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from?

A horizontal straight wire 10 m long extending from east to west is falling with a speed of

5.0 m s^{-1}

, at right angles to the horizontal component of the earth’s magnetic field,

0.30 \times 1 0^{-4} Wb m^{-2}

. (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

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Chapter 7: Alternating Current

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A horizontal straight wire 10 m long extending from east to west is falling with a speed of $5.0 m s^{-1}$ , at right angles to the horizontal component of the earth’s magnetic field, $0.30 \times 1 0^{-4} Wb m^{-2}$ . (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?

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Updated on: Oct 21, 2023

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Physics Part-I (NCERT)

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Elijah Discussed

A horizontal straight wire 10 m long extending from east to west is falling with a speed of

5.0 m s^{-1}

, at right angles to the horizontal component of the earth’s magnetic field,

0.30 \times 1 0^{-4} Wb m^{-2}

. (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

(a)

l = 10 c m, v = 5.0 m / s, B = 0.3 \times 1 0^{- 4} Wb m^{- 2}

Induce EMF is

e = Bl v = 1.5 \times 1 0^{- 3} V

(b)

Using Fleming’s right hand rule, it can be inferred that the direction of the induced emf is from West to East.

(c)

The west end of the wire is at a higher potential.

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Practice more questions from Physics Part-I (NCERT)

A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of in a uniform horizontal magnetic field of magnitude

3.0 \times 1 0^{-2 T}

A horizontal straight wire 10 m long extending from east to west is falling with a speed of

5.0 m s^{-1}

, at right angles to the horizontal component of the earth’s magnetic field,

0.30 \times 1 0^{-4} Wb m^{-2}

. (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?

Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average emf of 200 V induced, give an estimate of the self-inductance of the circuit.

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Question Text	A horizontal straight wire 10 m long extending from east to west is falling with a speed of $5.0 m s^{-1}$ , at right angles to the horizontal component of the earth’s magnetic field, $0.30 \times 1 0^{-4} Wb m^{-2}$ . (a) What is the instantaneous value of the emf induced in the wire? (b) What is the direction of the emf? (c) Which end of the wire is at the higher electrical potential?
Updated On	Oct 21, 2023
Topic	Electromagnetic Induction
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 4
Upvotes	445
Avg. Video Duration	10 min

Text solutionVerified

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