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Physics Part-II

Wave Optics

A beam of light consisting of two wavelengths, 650 nm and 520

Physics Part-II

Class 12

NCERT

Chapter 1: Ray Optics and Optical Instruments

41 questions

Chapter 2: Wave Optics

30 questions

In Youngs double-slit experiment using monochromatic light of wavelength

λ

, the intensity of light at a point on the screen where path difference is

λ

, is K units. What is the intensity of light at a point where path difference is

λ

/3?

A beam of light consisting of two wavelengths,

650 nm

and

520 nm

, is used to obtain interference fringes in a Young's double-slit experiment.(a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength

650 nm

.(b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the two slits is

0.28 mm

and the screen is at a distance of

1.4 m

from the slits.

In a double-slit experiment the angular width of a fringe is found to be

0. 2^{o}

on a screen placed

1 m

away. The wavelength of light used is

600 nm

. What will be the angular width of the fringe is the entire experimental apparatus is immersed in water? Take refractive index of water to be

\frac{4}{3}

View all question

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Question

Easy

Solving time: 4 mins

A beam of light consisting of two wavelengths, $650 nm$ and $520 nm$ , is used to obtain interference fringes in a Young's double-slit experiment.(a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength $650 nm$ .(b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the two slits is $0.28 mm$ and the screen is at a distance of $1.4 m$ from the slits.

Views: 5,833 students

Updated on: Mar 8, 2023

Book:

Physics Part-II (NCERT)

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William Discussed

A beam of light consisting of two wavelengths,

650 nm

and

520 nm

, is used to obtain interference fringes in a Young's double-slit experiment.(a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength

650 nm

.(b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the two slits is

0.28 mm

and the screen is at a distance of

1.4 m

from the slits.

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Given

The wavelength of the light is

λ_{1} = 650 nm

The wavelength of seond light,

λ_{2} = 520 nm

Distance between the slit and the screen is

1.4 m

Distance between the slits is

0.28 mm

(a)

The relation between the

n^{t h}

bright fringe and the width of fringe is:

x = n λ_{1} \frac{D}{d}

For third bright fringe,

n = 3

x = 3 \times 650 \frac{1.4}{0.28 \times 1 0 ^{- 3}} = 1950 \times 5 \times 1 0^{3} nm

x = 9.75 \times 1 0^{- 3} m

= 9.75 mm

(b)

We can consider that

n^{t h}

bright frind of

λ_{2}

and the

(n - 1)^{t h}

bright fringe of wavelength

λ_{1}

coincide with each other.

n λ_{2} = (n - 1) λ_{1}

520 n = 650 n - 650

650 = 130 n

n = 5

therefore, the least distance from the central maximum can be obtained as:

x^{'} = n λ_{2} \frac{D}{d}

x^{'} = 5 \times 520 \frac{D}{d} = 2600 \frac{1.4}{0.28 \times 1 0 ^{- 3}} nm

x^{'} = 1.30 \times 1 0^{- 2} m = 1.3 c m

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Practice more questions from Physics Part-II (NCERT)

In Youngs double-slit experiment using monochromatic light of wavelength

λ

, the intensity of light at a point on the screen where path difference is

λ

, is K units. What is the intensity of light at a point where path difference is

λ

/3?

A beam of light consisting of two wavelengths,

650 nm

and

520 nm

, is used to obtain interference fringes in a Young's double-slit experiment.(a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength

650 nm

.(b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the two slits is

0.28 mm

and the screen is at a distance of

1.4 m

from the slits.

In a double-slit experiment the angular width of a fringe is found to be

0. 2^{o}

on a screen placed

1 m

away. The wavelength of light used is

600 nm

. What will be the angular width of the fringe is the entire experimental apparatus is immersed in water? Take refractive index of water to be

\frac{4}{3}

View all

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Question Text	A beam of light consisting of two wavelengths, $650 nm$ and $520 nm$ , is used to obtain interference fringes in a Young's double-slit experiment.(a) Find the distance of the third bright fringe on the screen from the central maximum for wavelength $650 nm$ .(b) What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide? The distance between the two slits is $0.28 mm$ and the screen is at a distance of $1.4 m$ from the slits.
Updated On	Mar 8, 2023
Topic	Wave Optics
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 13
Upvotes	1432
Avg. Video Duration	9 min

Text solutionVerified

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