Chemistry Part-II
Class 12
NCERT
1
Chapter 1: Haloalkanes and Haloarenes
33 questions
2
Chapter 2: Alcohols, Phenols and Ethers
38 questions
Q1
Name the reagents used in the following reactions:
(i) Oxidation of a primary alcohol to carboxylic acid.
(ii) Oxidation of a primary alcohol to aldehyde.
(iii) Bromination of phenol to 2,4,6-tribromophenol.
(iv) Benzyl alcohol to benzoic acid.
(v) Dehydration of propan-2-ol to propene.
(vi) Butan-2-one to butan-2-ol.
(i) Oxidation of a primary alcohol to carboxylic acid.
(ii) Oxidation of a primary alcohol to aldehyde.
(iii) Bromination of phenol to 2,4,6-tribromophenol.
(iv) Benzyl alcohol to benzoic acid.
(v) Dehydration of propan-2-ol to propene.
(vi) Butan-2-one to butan-2-ol.
Q2
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
Q3
Give IUPAC names of the following ethers:
View all question3
Chapter 3: Aldehydes, Ketones and Carboxylic Acids
26 questions
4
Chapter 4: Amines
18 questions
5
Chapter 5: Biomolecules
25 questions
6
Chapter 6: Polymers
21 questions
7
Chapter 7: Chemistry in Everyday Life
27 questions
Question
Easy
Solving time: 1 mins
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
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Text solution
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Due to presence of group in ethanol, intermolecular hydrogen bonding leads to molecular association. To break this molecular association and hydrogen bonds, extra energy is required. This results in high boiling point.
In methoxymethane, hydrogen bonding is not possible. This results in lower boiling point.
Hence, the boiling point of ethanol is higher in comparison to methoxymethane.
In methoxymethane, hydrogen bonding is not possible. This results in lower boiling point.
Hence, the boiling point of ethanol is higher in comparison to methoxymethane.
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Practice more questions from Chemistry Part-II (NCERT)
Q1
Name the reagents used in the following reactions:
(i) Oxidation of a primary alcohol to carboxylic acid.
(ii) Oxidation of a primary alcohol to aldehyde.
(iii) Bromination of phenol to 2,4,6-tribromophenol.
(iv) Benzyl alcohol to benzoic acid.
(v) Dehydration of propan-2-ol to propene.
(vi) Butan-2-one to butan-2-ol.
(i) Oxidation of a primary alcohol to carboxylic acid.
(ii) Oxidation of a primary alcohol to aldehyde.
(iii) Bromination of phenol to 2,4,6-tribromophenol.
(iv) Benzyl alcohol to benzoic acid.
(v) Dehydration of propan-2-ol to propene.
(vi) Butan-2-one to butan-2-ol.
Q2
Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
Q3
Give IUPAC names of the following ethers:
View allPractice questions from Chemistry Part-II (NCERT)
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| Question Text | Give reason for the higher boiling point of ethanol in comparison to methoxymethane. |
| Topic | Alcohols, Phenols and Ethers |
| Subject | Chemistry |
| Class | Class 12 |
| Answer Type | Text solution:1 |
| Upvotes | 67 |
