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Chemistry Part-I

Structure of Atom

A photon of wavelength 4 { 10 }^{ -7 } m strikes on a metal s

Chemistry Part-I

Class 11

NCERT

Chapter 1: Some Basic Concepts of Chemistry

44 questions

Chapter 2: Structure of Atom

85 questions

What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

A photon of wavelength

4 \times 10^{- 7}

m strikes on a metal surface, the work function of the metal is 2.13 eV.

Calculate:

(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.

[1 e V = 1.6020 \times 10^{- 19} J]

A 25 watt bulb emits monochromatic yellow light of wavelength of

0.57 μ m

. Calculate the rate of emission of quanta per second.

View all question

Chapter 3: Classification of Elements and Periodicity in Properties

50 questions

Chapter 4: Chemical Bonding and Molecular Structure

44 questions

Chapter 5: States of Matter

28 questions

Chapter 6: Thermodynamics and Thermochemistry

36 questions

Chapter 7: Equilibrium

101 questions

Question

Medium

Solving time: 6 mins

A photon of wavelength $4 \times 10^{- 7}$ m strikes on a metal surface, the work function of the metal is 2.13 eV.
Calculate:
(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.
$[1 e V = 1.6020 \times 10^{- 19} J]$ .

Name: Video solution 1: [Solved] A photon of wavelength 4×10−7 m strikes on a metal surface, the work function of the metal is 2.13 eV. Calculate:(i) The energy of the photon (eV)(ii) The kinetic energy of the emission(iii) The velocity of the photoelectron. [1eV=1.6020× 10−19J]. - Chemistry Part-I
Uploaded: 2023-09-10T10:38:41.000Z
Duration: 6 min
Description: Video solution 1: [Solved] A photon of wavelength 4×10−7 m strikes on a metal surface, the work function of the metal is 2.13 eV. Calculate:(i) The energy of the photon (eV)(ii) The kinetic energy of the emission(iii) The velocity of the photoelectron. [1eV=1.6020× 10−19J]. - Chemistry Part-I

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Updated on: Sep 10, 2023

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Chemistry Part-I (NCERT)

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A photon of wavelength

4 \times 10^{- 7}

m strikes on a metal surface, the work function of the metal is 2.13 eV.

Calculate:

(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.

[1 e V = 1.6020 \times 10^{- 19} J]

10 mins ago

Discuss this question LIVE

10 mins ago

Text solutionVerified

(i)The energy of the photon is

E = \frac{h c}{λ}

= \frac{6.626 \times 1 0 ^{- 34} J s \times 3 \times 1 0 ^{8} m / s}{4.0 \times 1 0 ^{- 7} m}

= 4.97 \times 1 0^{- 19} J

Convert the unit into electron volts.

E = \frac{4.97 \times 1 0 ^{- 19}}{1.602 \times 1 0 ^{- 19}} = 3.10 e V

(ii) The kinetic energy of emission is

K . E = h ν - h ν_{o} = 3.10 e V - 2.13 e V = 0.97 e V

(iii) The expression for the velocity of emitted photoelectron is

v = \frac{2 K . E}{m}

= \frac{2 \times 0.97 \times 1.602 \times 1 0 ^{- 19}}{9.11 \times 1 0 ^{- 31}} = 5.84 \times 1 0^{5} m / s

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Practice more questions from Chemistry Part-I (NCERT)

What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?

A photon of wavelength

4 \times 10^{- 7}

m strikes on a metal surface, the work function of the metal is 2.13 eV.

Calculate:

(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.

[1 e V = 1.6020 \times 10^{- 19} J]

A 25 watt bulb emits monochromatic yellow light of wavelength of

0.57 μ m

. Calculate the rate of emission of quanta per second.

View all

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Question Text	A photon of wavelength $4 \times 10^{- 7}$ m strikes on a metal surface, the work function of the metal is 2.13 eV. Calculate: (i) The energy of the photon (eV) (ii) The kinetic energy of the emission (iii) The velocity of the photoelectron. $[1 e V = 1.6020 \times 10^{- 19} J]$ .
Updated On	Sep 10, 2023
Topic	Structure of Atom
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 1
Upvotes	152
Avg. Video Duration	6 min

A photon of wavelength $4 \times 10^{- 7}$ m strikes on a metal surface, the work function of the metal is 2.13 eV.
Calculate:
(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.
$[1 e V = 1.6020 \times 10^{- 19} J]$ .

Text solutionVerified

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A photon of wavelength 4×10−7 m strikes on a metal surface, the work function of the metal is 2.13 eV. Calculate:(i) The energy of the photon (eV)(ii) The kinetic energy of the emission(iii) The velocity of the photoelectron. [1eV=1.6020× 10−19J].

Text solutionVerified

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A photon of wavelength $4 \times 10^{- 7}$ m strikes on a metal surface, the work function of the metal is 2.13 eV.
Calculate:
(i) The energy of the photon (eV)
(ii) The kinetic energy of the emission
(iii) The velocity of the photoelectron.
$[1 e V = 1.6020 \times 10^{- 19} J]$ .