A teacher wants to justify to their department the value of allowing students to use a formula sheet for reference during assessments.The teacher randomly selects 60 students throughout the department and pairs them by test average. On the next test, half the students are given a formula sheet and half the students are not. The hypothesis test for the difference in test score means has a P-value of 0.2927 and the confidence interval at the 95 % confidence level is (0.69, 4.64) (a) Is there enough evidence to reject the null hypothesis? Yes, there is a less than 5 % chance of seeing a mean difference in test scores as high as this sample No, there is a more than 5 % chance of seeing a mean difference in test scores as high as this sample No.there is a less than 5 % chance of seeing a mean difference in test scores as high as this sample Yes, there is a more than 5 % chance of seeing a mean difference in test scores as high as this sample (b) Does the confidence interval provide strong evidence that there is a difference in average test scores? Yes, we are 95 % confident that students with a formula sheet score 0.69 to 4.64 points higher than students without which is a large increase in scores No.we are 95 % confident that students with a formula sheet score 0.69 to 4.64 points higher than students without which means its plausible to have only a minor increase in scores Submit

Views: 5,480 students