The exergy at the initial state.

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(a)

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The exergy at the initial state.

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The T−v diagram with initial and final condition of the water is shown below.

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Figure-(1)

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Write the expression for the exergy at the initial state.

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E1=m[(u1−u0)+p0(v1−v0)−T0(s1−s0)+V122000+gz11000] (I)

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Here, the mass of the water is m, the specific internal energy at the point 1 of the water is u1, the specific internal energy of the dead state is u0, the atmospheric pressure is p0, the specific volume at the point is v1, the specific volume at the dead state is v0, the specific entropy at the point 1 is s1, the specific entropy at the dead state is s0, the velocity of the water at point 1 is V1, the acceleration due to gravity is g and the elevation at the state 1is z1.

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Conclusion:

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Substitute 1\u2009kg for m, 298\u2009K for T0, 25\u2009m/s for V1, 9.81\u2009m/s2 for g, 5\u2009m for z1 100\u2009kPa for p0, 1.673\u2009m3/kg for v1,0.00010029\u2009m3/kg for v0, 7.3549\u2009kJ/kg⋅K for s1, 0.3674\u2009kJ/kg⋅K for s0,2506

', 'sectionSequence': 2, 'computed': {'sectionNameWithHtmlRemoved': 'Explanation', 'sectionTextWithHtmlRemoved': 'The T − v diagram with initial and final condition of the water is shown below. Figure-(1) Write the expression for the exergy at the initial state. E 1 = m [ ( u 1 − u 0 ) + p 0 ( v 1 − v 0 ) − T 0 ( s 1 − s 0 ) + V 1 2 2000 + g z 1 1000 ] (I) Here, the mass of the water is m , the specific internal energy at the point 1 of the water is u 1 , the specific internal energy of the dead state is u 0 , the atmospheric pressure is p 0 , the specific volume at the point is v 1 , the specific volume at the dead state is v 0 , the specific entropy at the point 1 is s 1 , the specific entropy at the dead state is s 0 , the velocity of the water at point 1 is V 1 , the acceleration due to gravity is g and the elevation at the state 1is z 1 . Conclusion: Substitute 1 kg for m , 298 K for T 0 , 25 m / s for V 1 , 9.81 m / s 2 for g , 5 m for z 1 100 kPa for p 0 , 1.673 m 3 / kg for v 1 , 0.00010029 m 3 / kg for v 0 , 7.3549 kJ / kg ⋅ K for s 1 , 0.3674 kJ / kg ⋅ K for s 0 , 2506'}}]}, {'sectionSequence': 1, 'sectionHeaderText': '

(b)

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The exergy at the final state.

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(c)

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The change in exergy.

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