The consumption of natural gas by a company satisfies the empirical equation $V=1.50t+0.00800t^2$, where $V$ is the volume of gas in millions of cubic feet and $t$ is the time in months. Express this equation in units of cubic feet and seconds. Assume a month is 30.0 days.

Key Concepts: Unit Conversion, Dimensional Analysis, Quadratic Equations Explanation: The equation relates the volume of gas consumed (V) to the time (t) in months. We are asked to express this equation in cubic feet and seconds. Step by Step Solution: Step 1. Convert the time unit from months to seconds. Since there are 30.0 days in a month, we have 1 month = 30.0 days. And since there are 24 hours in a day and 3600 seconds in an hour, we can write: \n 1 month = 30.0 days \u00D7 24 hours/day \u00D7 3600 seconds/hour = 2,592,000 seconds. Step 2. To convert the volume unit from millions of cubic feet to cubic feet, we simply multiply by 1,000,000. So we have V = (1.50 t + 0.00800 t^2) \u00D7 1,000,000. Step 3. Substitute 2,592,000 seconds for t in the equation from step 2:\n V = (1.50 \u00D7 2,592,000 + 0.00800 \u00D7 (2,592,000)^2) \u00D7 1,000,000 Step 4. Simplify and solve for V:\n V = 2.12 \u00D7 10^15 cubic feet Final Answer: V = 2.12 \u00D7 10^15 cubic feet