Answer Total cross femurs is A=2×10 m2=20×kgwt=400 N force acting on (ms−2 ). This force is acting vertically down and hence, normally on the directions in a femurs. Thus, the average pressure is that like other t
Pav=AF=2×105 N m−2
10.2.1 Pascal's Law
The French scientist Blaise Pascal observed that Now conside the pressure in a fluid at rest is the same at all horizontal bar points if they are at the same height. This fact is in equilibriu may be demonstrated in a simple way. at its two en
Fig. 10.2 Proof of Pascal's law. ABC-DEF is an Consider a element of the interior of a fluid at rest. Fig. 10.3 poin This element is in the form of a right- The pressure angled prism. The element is small so that respectively. the effect of gravity can be ignored, but it fluid having a has been enlarged for the sake of clarity. fluid is at re
Fig. 10.2 shows an element in the interior of should be zer a fluid at rest. This element ABC−DEF is in the should balan form of a right-angled prism. In principle, this forces acting prismatic element is very small so that every the fluid pi part of it can be considered at the same depth downward, a from the liquid surface and therefore, the effect If mg is weig of the gravity is the same at all these points. have But for clarity we have enlarged this element. (P2−P1)A The forces on this element are those exerted by Now, if ρ i the rest of the fluid and they must be normal to have the ma the surfaces of the elenient as discussed above. that Thus, the fluid exerts pressures Pa,Pb and Pc on P2−P1=ρg

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Answer Total cross femurs is A=2×10 m2=20×kgwt=400 N force acting on (ms−2 ). This force is acting vertically down and hence, normally on the directions in a femurs. Thus, the average pressure is that like other t
Pav​=AF​=2×105 N m−2
10.2.1 Pascal's Law
The French scientist Blaise Pascal observed that  Now conside the pressure in a fluid at rest is the same at all horizontal bar points if they are at the same height. This fact is in equilibriu may be demonstrated in a simple way. at its two en
Fig. 10.2 Proof of Pascal's law. ABC-DEF is an Consider a element of the interior of a fluid at rest. Fig. 10.3 poin This element is in the form of a right- The pressure angled prism. The element is small so that respectively. the effect of gravity can be ignored, but it fluid having a has been enlarged for the sake of clarity. fluid is at re
Fig. 10.2 shows an element in the interior of should be zer a fluid at rest. This element ABC−DEF is in the should balan form of a right-angled prism. In principle, this forces acting prismatic element is very small so that every the fluid pi part of it can be considered at the same depth downward, a from the liquid surface and therefore, the effect If mg is weig of the gravity is the same at all these points. have But for clarity we have enlarged this element. (P2​−P1​)A The forces on this element are those exerted by  Now, if ρ i the rest of the fluid and they must be normal to have the ma the surfaces of the elenient as discussed above. that Thus, the fluid exerts pressures Pa​,Pb​ and Pc​ on P2​−P1​=ρg

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Question Text	Answer Total cross femurs is $A = 2 \times 10 m^{2} = 20 \times kg wt = 400 N$ force acting on $(m s^{- 2}$ ). This force is acting vertically down and hence, normally on the directions in a femurs. Thus, the average pressure is that like other t $P_{a v} = \frac{F}{A} = 2 \times 1 0^{5} N m^{- 2}$ 10.2.1 Pascal's Law The French scientist Blaise Pascal observed that Now conside the pressure in a fluid at rest is the same at all horizontal bar points if they are at the same height. This fact is in equilibriu may be demonstrated in a simple way. at its two en Fig. 10.2 Proof of Pascal's law. ABC-DEF is an Consider a element of the interior of a fluid at rest. Fig. $10.3$ poin This element is in the form of a right- The pressure angled prism. The element is small so that respectively. the effect of gravity can be ignored, but it fluid having a has been enlarged for the sake of clarity. fluid is at re Fig. $10.2$ shows an element in the interior of should be zer a fluid at rest. This element $A BC - D EF$ is in the should balan form of a right-angled prism. In principle, this forces acting prismatic element is very small so that every the fluid pi part of it can be considered at the same depth downward, a from the liquid surface and therefore, the effect If $m g$ is weig of the gravity is the same at all these points. have But for clarity we have enlarged this element. $(P_{2} - P_{1}) A$ The forces on this element are those exerted by Now, if $ρ$ i the rest of the fluid and they must be normal to have the ma the surfaces of the elenient as discussed above. that Thus, the fluid exerts pressures $P_{a}, P_{b}$ and $P_{c}$ on $P_{2} - P_{1} = ρ g$
Updated On	Jan 30, 2023
Topic	Optics
Subject	Physics
Class	Class 12
Answer Type	Video solution: 1
Upvotes	109
Avg. Video Duration	1 min

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