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A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height ()
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Text solutionVerified
Sure, here are the step-by-step solutions:
Given:
Distance = 125m,
Time = 5s,
Initial velocity = 0
We need to find the acceleration of the object.
We can use the formula:
Distance = Initial Velocity * Time + 0.5 * Acceleration * Time^2
Since the initial velocity is 0, the formula simplifies to:
Distance = 0.5 * Acceleration * Time^2
Rearranging the formula, we get:
Acceleration = 2 * Distance / Time^2
Substituting the given values, we get:
Acceleration = 2 * 125m / (5s)^2
Simplifying, we get:
Acceleration = 10m/s^2
Therefore, the acceleration of the object is 10m/s^2.
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Question Text | A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height () |
Topic | Gravitation |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 |