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The magnitude of the electric field at a distance from a point charge is equal to How close to a water molecule (of polarizability volume ) must a proton approach before the dipole moment it induces has a magnitude equal to that of the permanent dipole moment of the molecule

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Key Concepts: Electric Field, Point Charge, Polarizability, Dipole Moment Explanation: We can use the formula for the induced dipole moment in a molecule due to an external electric field. We know that the induced dipole moment should have a magnitude of 1.85 D. We can equate this to the expression for dipole moment induced in a molecule due to an electric field, which is , where is the polarizability of the molecule and is the electric field, and solve for . Step by Step Solution: Step 1. Calculate the induced dipole moment of the water molecule using the given polarizability volume: . Recall that , where is the volume of the molecule and is the permittivity of free space. Therefore, = 2.99 x 10^-30 Cm. Step 2. Substitute the induced dipole moment and polarizability into the dipole moment induced expression: . Solve for : . Step 3. Use Coulomb's law to calculate the distance from the proton to the water molecule when it induces an electric field of this magnitude: , where is Coulomb's constant. Rearranging for : . Step 4. Substitute the values for , , and : . Final Answer: The proton must approach to a distance of m from the water molecule to induce a dipole moment with a magnitude equal to the permanent dipole moment of the molecule.
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Question Text
The magnitude of the electric field at a distance from a point charge is equal to How close to a water molecule (of polarizability volume ) must a proton approach before the dipole moment it induces has a magnitude equal to that of the permanent dipole moment of the molecule
TopicAll topics
SubjectChemistry
ClassClass 11
Answer TypeText solution:1