Identify structure of $\alpha$ -D-Xylofuranose

Step by Step Solution: Step 1. Identify the monosaccharide present in the structure, which is D-Xylofuranose Step 2. Determine the configuration of the anomeric carbon (carbon 1) by looking at the orientation of the hydroxyl (OH) group attached to it. In this case, the OH group is below the plane of the ring, indicating an alpha configuration. Step 3. Identify the type of ring present, which is a furanose ring. Furanose rings contain a five-membered ring structure with four carbons and one oxygen. Step 4. Determine the orientation of the substituents on the ring carbons, which is usually done by starting with the anomeric carbon and numbering the carbons clockwise or counterclockwise. In this case, the substituent on carbon 2 is an OH group and it is below the plane of the ring, while the substituent on carbon 5 is also an OH group and it is above the plane of the ring. Step 5. Compile all the structural features identified in the previous steps to obtain the complete structure of alpha-D-xylofuranose. Final Answer: The structure of alpha-D-xylofuranose is as follows: $\alpha -\mathrm{D}-\mathrm{xylofuranose}$