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Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ

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Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2 Δ G ∘ = − 394 kJ Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) .

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Text solutionVerified

Given: 2

H_{2}

+ C < C

H_{4}

Δ

^{\circ}

= -51 kJ 2

H_{2}

O_{2}

< 2

H_{2}

Δ

^{\circ}

= -474 kJ C +

O_{2}

< C

O_{2}

Δ

^{\circ}

= -394 kJ Algebraically Fixed Equations so Undesired Components Cancel Out (Add all

Δ

^{\circ}

values to get the final

Δ

^{\circ}

) : C

H_{4}

< 2

H_{2}

+ C/

Δ

^{\circ}

= +51 kJ 2

H_{2}

O_{2}

< 2

H_{2}

Δ

^{\circ}

= -474 kJ C +

O_{2}

< C

O_{2}

Δ

^{\circ}

= -394 kJ C

H_{4}

+ 2

O_{2}

< C

O_{2}

+ 2

H_{2}

Δ

^{\circ}

= -817 kJ/

m o l_{r x n}

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Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2 Δ G ∘ = − 394 kJ Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) .

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Question Text	Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2 Δ G ∘ = − 394 kJ Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) .
Topic	All topics
Subject	Chemistry
Class	Class 12
Answer Type	Text solution:1

Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2 Δ G ∘ = − 394 kJ Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) .

Text solutionVerified

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