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Diagram the lactose operon in E coll with the proper order of the Clements inct, lacc, lac , and lacz, and explain how expression is controlled in the presence and absence of lactose.

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LABORATORY REPORT: CELLULAR TRANSPORT AND ORGANIC MOLECULES Lab Section: 28543 Nanie Exadalue Data from Exercise 2.1: Diffusion through agar: Time (min) Methylene Blue (mm) Potassium Permanganate (mm) 0 0 0 2 1.5 4 4 3 8 6 4.5 14 8 6 18 10 7.5 23 12 9 28 Data from Exercise 2.1 (heated): Time (min) Methylene Blue (mm) Potassium Permanganate (mm) 0 0 0 2 1.5 4 4 3 8 6 4.5 14 8 6 18 10 7.5 23 12 9 28 Why do the dye molecules move? The dye molecules move due to the phenomenon called diffusion. The particles of the dye have kinetic energy, which causes them to move randomly and interact with each other, resulting in the diffusion. To calculate the rate of diffusion of potassium permanganate (mm/min) at room temperature and heated: Rate of diffusion at room temperature = (28 mm - 0 mm) / (12 min - 0 min) = 2.33 mm/min Rate of diffusion when heated = (28 mm - 0 mm) / (12 min - 0 min) = 2.33 mm/min To calculate the rate of diffusion of methylene blue (mm/min) at room temperature and heated: Rate of diffusion at room temperature = (9 mm - 0 mm) / (12 min - 0 min) = 0.75 mm/min Rate of diffusion when heated = (9 mm - 0 mm) / (12 min - 0 min) = 0.75 mm/min The dye molecules diffused more rapidly when heated. The rate of diffusion is inversely related to the molecular weight. The lighter the molecule, the faster it diffuses. This is because lighter molecules have higher kinetic energy and can move more quickly through the agar. Explanation for Q. 5: The rate of diffusion of methylene blue was higher than that of potassium permanganate, indicating that methylene blue diffused more rapidly. This can be attributed to the difference in molecular weight between the two dyes. Methylene blue has a lower molecular weight compared to potassium permanganate, making it lighter and allowing it to move more quickly through the agar. Rev: 1/20
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Question Text
Diagram the lactose operon in E coll with the proper order of the Clements inct, lacc, lac , and lacz, and explain how expression is controlled in the presence and absence of lactose.
TopicAll topics
SubjectBiology
ClassClass 11