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Chapter Sequences; Induction; The Binomial Theorem, Question Problem 14AYU

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RECALL: (1) For any natural number , (2) Use the definition in (1) above to obtain: \require{cancel} \dfrac{5!8!}{3!} \\=\dfrac{(5\cdot 4 \cdot 3\cdot2\cdot1)(8(7)(6)(5)(4)(3)(2)(1))}{(3)(2)(1)} \\=\dfrac{(5\cdot 4 \cancel{\cdot 3\cdot2\cdot1})(8(7)(6)(5)(4)(3)(2)(1))}{\cancel{(3)(2)(1)}} \\=\dfrac{5 \cdot (40320)}{1} \\= \dfrac{806,400}{1} \\=806,400
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Question Text
Chapter Sequences; Induction; The Binomial Theorem, Question Problem 14AYU
TopicAll Topics
SubjectAlgebra 2
ClassClass 12
Answer TypeText solution:1