The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition
A diatomic molecute has moment of inertie $1$ by Bohr's quantization condition its rotational energy in the $n^{t h}$ level $(n = 0 i s \neg a l l o w e d)$ is

Question

The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition
A diatomic molecute has moment of inertie

1

by Bohr's quantization condition its rotational energy in the

n^{t h}

level

(n = 0 i s \neg a l l o w e d)

is

Filo · Accepted Answer

Answer: DSolution: According to bohr's quantisation principle

L = \frac{n h}{2 π}

Rotational kinetic energy

= \frac{1}{2} 1 o m w g a^{2} = \frac{1}{2} I [\frac{L}{I}]^{3}

[∵ L = 1 ω]

= \frac{1}{2} \frac{L ^{2}}{I} = \frac{1}{2 I} = \frac{n ^{2} h ^{2}}{4 π ^{2} I} [2^{2} - 1^{2}]

[Fram(i)]

hv = (3h^(2))/(8 pi^(2)I

rArr I = (3h)/(8 pi^(2)v) = (3 xx 2 pi^(2) xx (4)/(pi) xx 10^(11) = (3)/(16) xx 10^(-445)

1.87 \times 10^{- 46} k g m^{2}

Question Text	The key feature of Bohr'[s spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton we will extend this to a general rotational motion to find quntized rotantized rotational energy of a diatomic molecule assuming it to be right . The rate to energy applied is Bohr's quantization condition A diatomic molecute has moment of inertie $1$ by Bohr's quantization condition its rotational energy in the $n^{t h}$ level $(n = 0 i s \neg a l l o w e d)$ is
Answer Type	Text solution:1
Upvotes	150

Text solutionVerified

Practice questions from similar books