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A metal is illumimated by light of two different wavelength {2

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A metal is illumimated by light of two different wavelength $248 n m$ and $310 n m$ . The maximum speeds of the photoelecrtron corresponding in these wavwlength are u_(1) and u_(2) $r e s p e c t i v e l y . I f t h e r a t i o u_{1} : u_{2} = 2 : 1$ and $h c = 1240 e V n m$ , the work function of the inetial is rearly

3.7 e V

3.2 e V

2.8 e V

2.5 e V

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A metal is illumimated by light of two different wavelength

248 n m

and

310 n m

. The maximum speeds of the photoelecrtron corresponding in these wavwlength are

u_(1) and u_(2)

r e s p e c t i v e l y . I f t h e r a t i o u_{1} : u_{2} = 2 : 1

and

h c = 1240 e V n m

, the work function of the inetial is rearly

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Text solutionVerified

Answer: ASolution:

\frac{h C}{λ _{1}} W = \frac{1}{2} μ_{1}^{2}

and (\frac{h C}{λ _{2}} W = \frac{1}{2} μ_{2}^{2}

D i v i d \in g t h e a b o v e t w o e q u a t i o n, w e \geq t

((hC)/(lambda_(1)) - W)/((hC)/(lambda_(2)) - W) ((hC)/(lambda_(1)) - W)/((hC)/(lambda_(2)) - W) (u_(1)^(2)/(u_(2)^(2)

\frac{\frac{1240}{248} - W}{\frac{1240}{310} - W = \frac{4}{1}}

∴ \frac{1240}{248} - W = \frac{4 \times 1240}{310} - 4 W

∴ W = 3.7 e V

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Question Text	A metal is illumimated by light of two different wavelength $248 n m$ and $310 n m$ . The maximum speeds of the photoelecrtron corresponding in these wavwlength are u_(1) and u_(2) $r e s p e c t i v e l y . I f t h e r a t i o u_{1} : u_{2} = 2 : 1$ and $h c = 1240 e V n m$ , the work function of the inetial is rearly
Answer Type	Text solution:1
Upvotes	150