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Electrostatic Potential and Capacitance

Parallel plate capacitors

The charges on two parallel copper plates separated by a small

Question

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Solving time: 2 mins

The charges on two parallel copper plates separated by a small distance are $+ Q$ and $- Q$ . A test charge $q$ experiences a force $F$ when placed between these plates. Now if one of the plates is removed to infinity, then the force on the test charge will become :

F /2

F

2 F

Zero

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Book:

Physics Galaxy Electrostatics and Current Electricity Vol 3 A (Ashish Arora)

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Charlotte Discussed

The charges on two parallel copper plates separated by a small distance are

+ Q

and

- Q

. A test charge

q

experiences a force

F

when placed between these plates. Now if one of the plates is removed to infinity, then the force on the test charge will become :

12 mins ago

Discuss this question LIVE

12 mins ago

Text solutionVerified

Electric field between the two plates is given as

E = \frac{σ}{\in _{0}}

Half of above electric field is contributed by one plate and remaining half is contributed by other plate. The electric field on the charge is given as

F = qE F = q \frac{σ}{ε _{0}}

If one plate is removed then electric field on the charge will be only due to the remaining plate which is half of the initial field so new force will beclome

F^{'} = q \frac{σ}{2 ε _{0}} = \frac{F}{2}

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Question Text	The charges on two parallel copper plates separated by a small distance are $+ Q$ and $- Q$ . A test charge $q$ experiences a force $F$ when placed between these plates. Now if one of the plates is removed to infinity, then the force on the test charge will become :
Topic	Electrostatic Potential and Capacitance
Subject	Physics
Class	Class 12
Answer Type	Text solution:1
Upvotes	141

The charges on two parallel copper plates separated by a small distance are $+ Q$ and $- Q$ . A test charge $q$ experiences a force $F$ when placed between these plates. Now if one of the plates is removed to infinity, then the force on the test charge will become :

Text solutionVerified

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The charges on two parallel copper plates separated by a small distance are $+ Q$ and $- Q$ . A test charge $q$ experiences a force $F$ when placed between these plates. Now if one of the plates is removed to infinity, then the force on the test charge will become :