Question
In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is
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[b] During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released = c (a + b) = c a b
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Question Text | In the reaction 21H+31H→42He+10n. If the tending energies of 21H, 31H and 42He are respectively a, b and c (in MeV), then the energy (in MeV) released in this reaction is |
Answer Type | Text solution:1 |
Upvotes | 150 |