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If the binding energy per nucleon in Li7and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7+p→2 2He4 is
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[d] B.E. of Li7=39.20 MeVand He4=28.24 MeVEnergy of reaction =56.48−39.20=17.28 MeV.
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Question Text | If the binding energy per nucleon in Li7and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7+p→2 2He4 is |
Answer Type | Text solution:1 |
Upvotes | 152 |