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Find the value of



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Text SolutionText solutionverified iconVerified

(c)



Solving these two equations, we get



(d) Apply

and

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Question 4
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1. WAVES AND HARMONICS So, for example, suppose that a piano tuner has tuned one of the three strings corresponding to the note A above middle C to 440 Hz. The second string is still out of tune, so that it resonates at 436 Hz. The third is being damped so as not to interfere with the tuning of the second string. Ignoring phase and amplitude for a moment, the two strings together will sound as sin(880t)+sin(872t) Using equation (1.8.9), we may rewrite this sum as 2 sin(876t)cos(4xt). This means that we perceive the combined effect as a sine wave with frequency 438 Hz, the average of the frequencies of the two strings, but with the amplitude modulated by a slow cosine wave with frequency 2 Hz, or half the difference between the frequencies of the two strings. This modulation is what we perceive as beats. The amplitude of the modulating cosine wave has two peaks per cycle, so the number of beats per second will be four, not two. So the number of beats per second is exactly the difference between the two frequencies. The piano tuner tunes the second string to the first by tuning out the beats, namely by adjusting the string so that the beats slow down to a standstill. If we wish to include terms for phase and amplitude, we write c1sin(880t)+c2sin(872t) where the angles θ1 and θ2 represent the phases of the two strings. This gets rewritten as c1sin(880t+θ1)+c2sin(872t+θ2) so this equation can be used to understand the relationship between the phase of the beats and the phases of the original sine waves. If the amplitudes are different, then the beats will not be so pronounced because part of the louder note is left over. This prevents the amplitude from going to zero when the modulating cosine takes the value zero. Exercises 1. A piano tuner comparing two of the three strings on the same note of a piano hears five beats a second. If one of the two notes is concert pitch A (440 Hz), what are the possibilities for the frequency of vibration of the other string?
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Question Text
Find the value of



Updated OnMar 16, 2023
TopicUnits and Measurements
SubjectPhysics
ClassClass 11
Answer TypeText solution:1 Video solution: 4
Upvotes451
Avg. Video Duration6 min