Question
Medium
Solving time: 3 mins
Calculate the potential due to a thin charged rod of length at the point along and perpendicular to its length.
Text solutionVerified
Suppose a thin rod has a uniform linear charge density . To find potential at point , let us divide the rod into a series of small elements of thickness each. Consider such an element at a distance from . The charge on the element
The potential due to the element at point
The potential due to the entire rod.
Was this solution helpful?
135
Share
Report
Found 2 tutors discussing this question
Discuss this question LIVE
9 mins ago
One destination to cover all your homework and assignment needs
Learn Practice Revision Succeed
Instant 1:1 help, 24x7
60, 000+ Expert tutors
Textbook solutions
Big idea maths, McGraw-Hill Education etc
Essay review
Get expert feedback on your essay
Schedule classes
High dosage tutoring from Dedicated 3 experts
Practice questions from Electrostatics (Disha)
Question 1
Medium
Views: 5,765
Question 2
Easy
Views: 5,650
Second conductor in the capacitor increases its capacitance.
Statement-2
Second conductor decreases the potential difference between the conductors.
Question 3
Medium
Views: 5,367
Question 4
Medium
Views: 6,000
Practice more questions from Electrostatic Potential and Capacitance
Question 2
Hard
Views: 5,139
Question 3
Medium
Views: 5,472
Question 4
Medium
Views: 6,280
Practice questions on similar concepts asked by Filo students
Question 1
Views: 5,710
Question 2
Views: 5,970
Question 3
Views: 5,336
Question 4
Views: 5,505
Stuck on the question or explanation?
Connect with our Physics tutors online and get step by step solution of this question.
231 students are taking LIVE classes
Question Text | Calculate the potential due to a thin charged rod of length at the point along and perpendicular to its length. |
Updated On | Nov 13, 2022 |
Topic | Electrostatic Potential and Capacitance |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 Video solution: 1 |
Upvotes | 221 |
Avg. Video Duration | 14 min |