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Physics Part-I

Current Electricity

At room temperature (27.0^o C) the resistance of a heating ele

Physics Part-I

Class 12

NCERT

Chapter 1: Electric Charges and Fields

47 questions

Chapter 2: Electrostatic Potential and Capacitance

46 questions

Chapter 3: Current Electricity

33 questions

(a) Three resistors

2Ω, 4Ω

and

5Ω

are combined in parallel. What is the total resistance of the combination?

(b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, detere the current through each resistor, and the total current drawn from the battery.

At room temperature

(27. 0^{o} C)

the resistance of a heating element is

100Ω

. What is the temperature of the element if the resistance is found to be

117Ω

, given that the temperature coefficient of the material of the resistor is

1.70 \times 1 0^{- 4} C^{- 1}

A negligibly small current is passed through a wire of length 15 m and uniform cross-section

6.0 \times 1 0^{- 7} m^{2}

, and its resistance is measured to be

5.0Ω

. What is the resistivity of the material at the temperature of the experiment?

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Chapter 4: Moving Charges and Magnetism

41 questions

Chapter 5: Magnetism and Matter

36 questions

Chapter 6: Electromagnetic Induction

28 questions

Chapter 7: Alternating Current

37 questions

Chapter 8: Electromagnetic Waves

20 questions

Question

Medium

Solving time: 4 mins

At room temperature $(27. 0^{o} C)$ the resistance of a heating element is $100Ω$ . What is the temperature of the element if the resistance is found to be $117Ω$ , given that the temperature coefficient of the material of the resistor is $1.70 \times 1 0^{- 4} C^{- 1}$ .

Views: 6,092 students

Updated on: May 31, 2022

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Physics Part-I (NCERT)

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At room temperature

(27. 0^{o} C)

the resistance of a heating element is

100Ω

. What is the temperature of the element if the resistance is found to be

117Ω

, given that the temperature coefficient of the material of the resistor is

1.70 \times 1 0^{- 4} C^{- 1}

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

T = 2 7^{o} C, R = 100Ω

R_{1} = 117Ω

thermal coefficient,

α = \frac{R _{1} - R}{R ( T _{1} - T )} = 1.70 \times 1 0^{- 4} C^{- 1}

\Rightarrow T_{1} = 102 7^{o} C

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Practice more questions from Physics Part-I (NCERT)

(a) Three resistors

2Ω, 4Ω

and

5Ω

are combined in parallel. What is the total resistance of the combination?

(b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, detere the current through each resistor, and the total current drawn from the battery.

At room temperature

(27. 0^{o} C)

the resistance of a heating element is

100Ω

. What is the temperature of the element if the resistance is found to be

117Ω

, given that the temperature coefficient of the material of the resistor is

1.70 \times 1 0^{- 4} C^{- 1}

A negligibly small current is passed through a wire of length 15 m and uniform cross-section

6.0 \times 1 0^{- 7} m^{2}

, and its resistance is measured to be

5.0Ω

. What is the resistivity of the material at the temperature of the experiment?

View all

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Question Text	At room temperature $(27. 0^{o} C)$ the resistance of a heating element is $100Ω$ . What is the temperature of the element if the resistance is found to be $117Ω$ , given that the temperature coefficient of the material of the resistor is $1.70 \times 1 0^{- 4} C^{- 1}$ .
Updated On	May 31, 2022
Topic	Current Electricity
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 6
Upvotes	624
Avg. Video Duration	4 min

At room temperature $(27. 0^{o} C)$ the resistance of a heating element is $100Ω$ . What is the temperature of the element if the resistance is found to be $117Ω$ , given that the temperature coefficient of the material of the resistor is $1.70 \times 1 0^{- 4} C^{- 1}$ .

Text solutionVerified

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At room temperature (27.0oC) the resistance of a heating element is 100Ω . What is the temperature of the element if the resistance is found to be 117Ω, given that the temperature coefficient of the material of the resistor is 1.70×10−4C−1.

Text solutionVerified

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At room temperature $(27. 0^{o} C)$ the resistance of a heating element is $100Ω$ . What is the temperature of the element if the resistance is found to be $117Ω$ , given that the temperature coefficient of the material of the resistor is $1.70 \times 1 0^{- 4} C^{- 1}$ .