An ideal coil of 10 {H} is connected in series with a resistan

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An ideal coil of $10 H$ is connected in series with a resistance of $5Ω$ and a battery of $5 V$ . $2 s$ after the connection is made, the current flowing (in ampere) in the circuit is

(1 - e)

e

e^{- 1}

(1 - e^{- 1})

Views: 5,996 students

Updated on: Sep 27, 2023

Text solutionVerified

Rise of current in

L - R

circuit is given by
Solution Image

I = I_{0} (1 - e^{- t / τ})

Where,

I_{0} = \frac{E}{R} = \frac{5}{5} = 1 A

Now,

τ = \frac{L}{R} = \frac{10}{5} = 2 s

After 2s, ie, at

t = 2 s

Rise of current

I = (1 - e^{- 1}) A

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Harper Discussed

An ideal coil of

10 H

is connected in series with a resistance of

5Ω

and a battery of

5 V

2 s

after the connection is made, the current flowing (in ampere) in the circuit is

8 mins ago

Discuss this question LIVE

8 mins ago

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Question Text	An ideal coil of $10 H$ is connected in series with a resistance of $5Ω$ and a battery of $5 V$ . $2 s$ after the connection is made, the current flowing (in ampere) in the circuit is
Updated On	Sep 27, 2023
Topic	Alternating Current
Subject	Physics
Class	Class 12
Answer Type	Text solution:1 Video solution: 8
Upvotes	656
Avg. Video Duration	9 min

An ideal coil of $10 H$ is connected in series with a resistance of $5Ω$ and a battery of $5 V$ . $2 s$ after the connection is made, the current flowing (in ampere) in the circuit is

Text solutionVerified

Video solutions (8)

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An ideal coil of 10H is connected in series with a resistance of 5Ω and a battery of 5 V. 2 s after the connection is made, the current flowing (in ampere) in the circuit is

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An ideal coil of $10 H$ is connected in series with a resistance of $5Ω$ and a battery of $5 V$ . $2 s$ after the connection is made, the current flowing (in ampere) in the circuit is