Question 1-7 are based on the following passage
Medium
Solving time: 3 mins
A spherical oil drop has a radius of . The density of the oil is .
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Show that the mass of the oil drop is .
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The oil drop is charged. Explain why it is impossible for the magnitude of the charge to be .
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The charged oil drop in (a) is in a vacuum between two horizontal metal plates, as illustrated in Fig. 4.1.
The plates are separated by a distance of . The electric field between the plates is uniform and has a field strength of .
The oil drop moves vertically downwards with a constant speed.
Calculate the potential difference between the plates.
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Explain how the motion of the oil drop shows that it is in equilibrium.
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Determine the charge on the oil drop.
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The magnitude of the potential difference between the plates in (b) is decreased.
Explain why the oil drop accelerates downwards
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Describe the change to the pattern of the field lines (lines of force) representing the uniform electric field as the potential difference decreases.
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Text solutionVerified
1. Mass is given as
2. As we know that the minimum charge on the drop is .
3. Potential difference between the plate is given as
4. Because it has constant velocity so no resultant force acts on it. So it is in equilibrium.
5.
sign of charge is negative
sign of charge is negative
6. Electric force decreases
So, weight electric force
or resultant force acts downwards.
So, weight electric force
or resultant force acts downwards.
7. The separation between electric field lines increases.
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Question Text | A spherical oil drop has a radius of . The density of the oil is . |
Topic | Density and pressure |
Subject | Physics |
Class | Grade 11 |