Question
Medium
Solving time: 3 mins
A simple pendulum of length is oscillating with an angular frequency 10 . The support of the pendulum starts oscillating up and down with a small angular frequency of and an amplitude of . The relative change in the angular frequency of the pendulum is best given by
Text solutionVerified
We know that time period of a pendulum is given by
So, angular frequency .....(i)
Now, differentiate both side w.r.t
.....(ii)
By dividing Eq. (ii) by Eq. (i), we get
]
Or we can write
.....(iii)
As is due to oscillation of support.
, support)
Putting value of in Eq. (iii) we get
So, angular frequency .....(i)
Now, differentiate both side w.r.t
.....(ii)
By dividing Eq. (ii) by Eq. (i), we get
]
Or we can write
.....(iii)
As is due to oscillation of support.
, support)
Putting value of in Eq. (iii) we get
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Question Text | A simple pendulum of length is oscillating with an angular frequency 10 . The support of the pendulum starts oscillating up and down with a small angular frequency of and an amplitude of . The relative change in the angular frequency of the pendulum is best given by |
Updated On | Feb 4, 2023 |
Topic | Oscillations |
Subject | Physics |
Class | Class 11 |
Answer Type | Text solution:1 Video solution: 10 |
Upvotes | 997 |
Avg. Video Duration | 7 min |