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A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is . After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of . What will be observed by the detector?

A
2 photons of energy

B
2 photons of energy

C
One photon of energy and an electron of energy

D
One photon of energy and another photon of energy

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The first photon will excite the hydrogen atom (in ground state) to first excited state (as ). Hence, during de-excitation a photon of will be released. The second photon of energy can ionise the atom. Hence, the balance energy, i.e. is retained by the electron. Therefore, by the second photon an electron of energy will be released.
Correct answer is (c).
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Question Text
A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is . After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of . What will be observed by the detector?
Updated OnApr 11, 2023
TopicAtoms
SubjectPhysics
ClassClass 12
Answer TypeText solution:1 Video solution: 11
Upvotes1185
Avg. Video Duration8 min