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A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is . After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of . What will be observed by the detector?
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The first photon will excite the hydrogen atom (in ground state) to first excited state (as ). Hence, during de-excitation a photon of will be released. The second photon of energy can ionise the atom. Hence, the balance energy, i.e. is retained by the electron. Therefore, by the second photon an electron of energy will be released.
Correct answer is (c).
Correct answer is (c).
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Question Text | A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is . After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of . What will be observed by the detector? |
Updated On | Apr 11, 2023 |
Topic | Atoms |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 Video solution: 11 |
Upvotes | 1185 |
Avg. Video Duration | 8 min |