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Mechanical Properties of Solids

Stress and strain

A person's femur (a long bone) has a diameter of 3.0 {cm} and

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Solving time: 3 mins

A person's femur (a long bone) has a diameter of $3.0$ $cm$ and a hollow centre of $0.8 cm$ diameter. Length of the bone is $50 cm$ . It is supporting a load of $600 N$ . How much will it be shortened by this load? Young's modulus of the bone is $Y = 1.6 \times 1 0^{10} Nm^{- 2}$ .

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Physics for JEE Main and Advanced Mechanics 2 (McGraw Hill)

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Camila Discussed

A person's femur (a long bone) has a diameter of

3.0

cm

and a hollow centre of

0.8 cm

diameter. Length of the bone is

50 cm

. It is supporting a load of

600 N

. How much will it be shortened by this load? Young's modulus of the bone is

Y = 1.6 \times 1 0^{10} Nm^{- 2}

5 mins ago

Discuss this question LIVE

5 mins ago

Text solutionVerified

Cross-sectional area supporting the load is

A Δ L = π [(\frac{3}{2})^{2} - (\frac{0.8}{2})^{2}] cm^{2} = \frac{F L}{A Y}

Substituting the values (in SI unit) will give the answer

2.9 \times 1 0^{- 5} m

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Question Text	A person's femur (a long bone) has a diameter of $3.0$ $cm$ and a hollow centre of $0.8 cm$ diameter. Length of the bone is $50 cm$ . It is supporting a load of $600 N$ . How much will it be shortened by this load? Young's modulus of the bone is $Y = 1.6 \times 1 0^{10} Nm^{- 2}$ .
Topic	Mechanical Properties of Solids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	85

A person's femur (a long bone) has a diameter of $3.0$ $cm$ and a hollow centre of $0.8 cm$ diameter. Length of the bone is $50 cm$ . It is supporting a load of $600 N$ . How much will it be shortened by this load? Young's modulus of the bone is $Y = 1.6 \times 1 0^{10} Nm^{- 2}$ .

Text solutionVerified

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A person's femur (a long bone) has a diameter of 3.0 cm and a hollow centre of 0.8 cm diameter. Length of the bone is 50 cm. It is supporting a load of 600 N. How much will it be shortened by this load? Young's modulus of the bone is Y=1.6×1010Nm−2.

Text solutionVerified

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A person's femur (a long bone) has a diameter of $3.0$ $cm$ and a hollow centre of $0.8 cm$ diameter. Length of the bone is $50 cm$ . It is supporting a load of $600 N$ . How much will it be shortened by this load? Young's modulus of the bone is $Y = 1.6 \times 1 0^{10} Nm^{- 2}$ .