Physics

Motion in a Plane

Angular momentum

A particle of mass 20 {~g} is released with an initial velocit

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A particle of mass $20 g$ is released with an initial velocity $5 m / s$ along the curve from the point $A$ , as shown in the figure. The point $A$ is at height $h$ from point $B$ . The particle slides along the frictionless surface. When the particle reaches point $B$ , its angular momentum about $O$ will be (Take, $g = 10 m / s^{2})$

Name: Video answer for A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be (Take, g=10 m/s2)
Uploaded: 2022-06-18T16:23:55.000Z
Duration: 5 min
Description: A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be (Take, g=10 m/s2)

8 kg - m^{2} / s

3 kg - m^{2} / s

2 kg - m^{2} /s

6 kg - m^{2} / s

Views: 5,543 students

Updated on: Sep 7, 2022

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2019

Text solutionVerified

The given figure is shown below as
Solution Image

As friction is absent, energy at

A =

energy at

B

\Rightarrow \frac{1}{2} m v_{A}^{2} + m g h = \frac{1}{2} m v_{B}^{2}

\Rightarrow v_{A}^{2} + 2 g h = v_{B}^{2}

v_{B}^{2} = (5)^{2} + 2 \times 10 \times 10 = 225

\Rightarrow v_{B} = 15 ms^{- 1}

Angular momentum about point '

O

= m v_{B} r_{B}

= 20 \times 1 0^{- 3} \times 15 \times 20

= 6 kg - m^{2} s^{- 1}

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Mila Discussed

A particle of mass

20 g

is released with an initial velocity

5 m / s

along the curve from the point

A

, as shown in the figure. The point

A

is at height

h

from point

B

. The particle slides along the frictionless surface. When the particle reaches point

B

, its angular momentum about

O

will be (Take,

g = 10 m / s^{2})

5 mins ago

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Question Text	A particle of mass $20 g$ is released with an initial velocity $5 m / s$ along the curve from the point $A$ , as shown in the figure. The point $A$ is at height $h$ from point $B$ . The particle slides along the frictionless surface. When the particle reaches point $B$ , its angular momentum about $O$ will be (Take, $g = 10 m / s^{2})$
Updated On	Sep 7, 2022
Topic	Motion in a Plane
Subject	Physics
Class	Class 11
Answer Type	Text solution:1 Video solution: 2
Upvotes	162
Avg. Video Duration	15 min

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