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Applications of Bernoulli's Theorem

In a given U-tube (open at one end and closed at other ends as

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Solving time: 3 mins

In a given U-tube (open at one end and closed at other ends as shown) find out the correct relation between $p$ and $p_{atm}$ : Given $d_{2} = 2 \times 13.6 gm / cm^{3} d_{1} = 13.6 gm / cm^{3}$

p_{atm} = p

p_{atm} = 2 p

p_{atm} = p /2

p_{atm} = p /4

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Book:

Physics Galaxy Mechanics Vol 1 (Ashish Arora)

Text solutionVerified

Pressure in a liquid at the same level is the same, so we use Pascal's equation from the open end
Solution Image

p_{a t m} + d_{2} y g + x d_{1} g = p In C.GSS. p_{a t m} + 13.6 \times 2 \times 25 \times g + 13.6 \times 26 \times g = p p_{a t m} + 13.6 \times g (50 + 26) = p

P_{a t m} = 13.6 \times g \times 76

so we use

\Rightarrow P_{a t m} = \frac{p}{2}

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In a given U-tube (open at one end and closed at other ends as shown) find out the correct relation between

p

and

p_{atm}

: Given

d_{2} = 2 \times 13.6 gm / cm^{3} d_{1} = 13.6 gm / cm^{3}

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Question Text	In a given U-tube (open at one end and closed at other ends as shown) find out the correct relation between $p$ and $p_{atm}$ : Given $d_{2} = 2 \times 13.6 gm / cm^{3} d_{1} = 13.6 gm / cm^{3}$
Topic	Mechanical Properties of Fluids
Subject	Physics
Class	Class 11
Answer Type	Text solution:1
Upvotes	85

In a given U-tube (open at one end and closed at other ends as shown) find out the correct relation between $p$ and $p_{atm}$ : Given $d_{2} = 2 \times 13.6 gm / cm^{3} d_{1} = 13.6 gm / cm^{3}$

Text solutionVerified

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Text solutionVerified

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In a given U-tube (open at one end and closed at other ends as shown) find out the correct relation between $p$ and $p_{atm}$ : Given $d_{2} = 2 \times 13.6 gm / cm^{3} d_{1} = 13.6 gm / cm^{3}$