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A hemispherical bowl of radius is rotated about its vertical axis. A small particle is kept on its inner surface where the radius makes an angle with the vertical. The particle rotates with the bowl without any slipping. The friction coefficient between the block and the bowl surface is . Find the range of the angular speed for which the block will not slip.

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If the bowl rotates at maximum angular speed, the block tends to slip upwards. So, the frictional force acts downward.
Here,
From FBD -1
(i) [because ]
and (ii)
Substituting the value of from (i) in Eq(ii). it can be found out that
Solution Image
Again, for minimum speed, the frictional force acts upward. From FBD-2, it can be proved that,

the range of speed is between and
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Question Text
A hemispherical bowl of radius is rotated about its vertical axis. A small particle is kept on its inner surface where the radius makes an angle with the vertical. The particle rotates with the bowl without any slipping. The friction coefficient between the block and the bowl surface is . Find the range of the angular speed for which the block will not slip.
Updated OnOct 12, 2023
TopicSystem of Particles and Rotational Motion
SubjectPhysics
ClassClass 11
Answer TypeText solution:1 Video solution: 5
Upvotes593
Avg. Video Duration10 min