Question
Medium
Solving time: 5 mins
A conducting wire of length l, lying normal to a magnetic field B, moves with a velocity v,as shown in the figure.
(a) Find the average magnetic force on a free electron of the wire.
(b) Due to this magnetic force, electrons concentrate at one end, resulting in an electric field inside the wire. The redistribution stops when the electric force on the free electrons balances the magnetic force. Find the electric field developed inside the wire when the redistribution stops.
(c) What potential difference is developed between the ends of the wire?
Text solutionVerified
Given:-
Length of the conducting wire =
Inward magnetic field
Velocity of the conducting wire
As the wire is moving with velocity , we can consider this as the net motion of electrons inside the wire with velocity .
(a) The average magnetic force on a free electron of the wire
, where is the charge of an electron.
(b) The redistribution stops when the electric force is just balanced by the magnetic force.
Electric force, and also magnetic force,
On equating the two forces, we get:-
(c) The potential difference is developed between the ends of the wire:
, where is the potential difference across the ends of the wire.
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Question Text | A conducting wire of length l, lying normal to a magnetic field B, moves with a velocity v,as shown in the figure. (a) Find the average magnetic force on a free electron of the wire. (b) Due to this magnetic force, electrons concentrate at one end, resulting in an electric field inside the wire. The redistribution stops when the electric force on the free electrons balances the magnetic force. Find the electric field developed inside the wire when the redistribution stops. (c) What potential difference is developed between the ends of the wire? |
Updated On | Sep 2, 2022 |
Topic | Moving Charges and Magnetism |
Subject | Physics |
Class | Class 12 |
Answer Type | Text solution:1 Video solution: 1 |
Upvotes | 159 |
Avg. Video Duration | 13 min |