Essential Cell Biology

Chapter 2

Essential Cell Biology 4th Edition by Alberts, Bruce; Bray, Dennis; Hopkin, Karen; Johnson, Alexander D; Lewis, Julian; Raff, Martin; Roberts, Keith; Walter, Peter

Essential Cell Biology 4th Edition Edition

Alberts, Bruce; Bray, Dennis; Hopkin, Karen; Johnson, Alexander D; Lewis, Julian; Raff, Martin; Roberts, Keith; Walter, Peter

Garland Science

High School Biology

Chapter 1: Chapter 1

18 questions

Chapter 2: Chapter 2

19 questions

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Chapter 3: Chapter 3

20 questions

Chapter 4: Chapter 4

15 questions

Chapter 5: Chapter 5

14 questions

Chapter 6: Chapter 6

16 questions

Chapter 7: Chapter 7

15 questions

Chapter 8: Chapter 8

5 questions

Chapter 9: Chapter 9

6 questions

Chapter 10: Chapter 10

14 questions

Chapter 11: Chapter 11

19 questions

Chapter 12: Chapter 12

23 questions

Chapter 13: Chapter 13

8 questions

Chapter 14: Chapter 14

24 questions

Chapter 15: Chapter 15

17 questions

Chapter 16: Chapter 16

10 questions

Chapter 17: Chapter 17

21 questions

Chapter 18: Chapter 18

19 questions

Chapter 19: Chapter 19

14 questions

Chapter 20: Chapter 20

6 questions

Question

Chemical Components Of Cells - Factoring Polynomials - Problem 11bQ

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Text solutionVerified

To determine the answer to this question we first need to know the volume of one page, which can be determined by the dimensions of one page.

(= 21.2 c m \times 27.6 c m \times 0.07 mm)

gives us a page volume of

4 \times 1 0^{-6} m^{3}

. This volume also happens to match the volume of a cube with a side length of 1.6 cm

(= 3\sqrt4 \times 1 0^{-6} m^{2})

. Question 2-11 A gave us the

1 0^{23}

atoms as the the amount of carbon atoms in the page.

3\sqrt1 0^{23}

gives us 4.6 × 10^7, the amount of carbon atoms lined up on each side of the cube. If we take

(= 4.6 \times 1 0^{7} \times 0.07 \times 1 0^{-3} m /1.6 \times 1 0^{-2} m)

we get 200,00 carbon atoms for the page thickness.

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Question Text	Chemical Components Of Cells - Factoring Polynomials - Problem 11bQ
Answer Type	Text solution:1