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Three mole of electrons are passed through three solutions in

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Three mole of electrons are passed through three solutions in succession containing $A g N O_{3}, C u S O_{4}$ and $A u C l_{3}$ respectively. The ratio of amounts of cations reduced at cathode will be___________.

1 : 2 : 3

2 : 1 : 3

3 : 2 : 1

6 : 3 : 2

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Three mole of electrons are passed through three solutions in succession containing

A g N O_{3}, C u S O_{4}

and

A u C l_{3}

respectively. The ratio of amounts of cations reduced at cathode will be___________.

15 mins ago

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15 mins ago

Text solutionVerified

Faraday's first law:-

The amount of substance that undergoes oxidation or reduction at each electrode during electrolysis is directly proportional to the amount of electricity that passes through the cell.

A g^{+} + 1 e^{-} \to A g

-----------[reduction at cathode]

1 mole of electron reduces 1 mole of

A g

\to

1 mole of

e^{-} \to

1 mole of

A g

∴

3 moles of

e^{-} \to ?

∴

Moles of

A g

reduced

= 3

ii)

C u^{2 +} + 2 e \to C u

\to 2 m o l e e^{-} \to 1 m o l e C u

∴

3 moles of

e^{-} \to ?

∴

Moles of

C u

reduced

= \frac{3}{2}

iii)

A u^{3 +} + 3 e^{-} \to A u

\to

3 mole of

e^{-} \to 1 m o l e A u

∴

moles of

A u

reduced

= 1

∴ R a t i o = 3 : \frac{3}{2} : 1 \to

Converting into whole number

= 6 : 3 : 2

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Question Text	Three mole of electrons are passed through three solutions in succession containing $A g N O_{3}, C u S O_{4}$ and $A u C l_{3}$ respectively. The ratio of amounts of cations reduced at cathode will be___________.
Answer Type	Text solution:1
Upvotes	150

Three mole of electrons are passed through three solutions in succession containing AgNO3​,CuSO4​ and AuCl3​ respectively. The ratio of amounts of cations reduced at cathode will be___________.

Text solutionVerified

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Three mole of electrons are passed through three solutions in succession containing $A g N O_{3}, C u S O_{4}$ and $A u C l_{3}$ respectively. The ratio of amounts of cations reduced at cathode will be___________.