Classically, an electron can be in any orbit around the nucleus of an atom. Then what determines the typical atomic size? Why is an atom not, say, thousand times bigger than its typical size? The question had greatly puzzled Bohr before he arrived at his famous model of the atom that you have learnt in the text. To simulate what he might well have done before his discovery, let us play as follows with the basic constants of nature and see if we can get a quantity with the dimensions of length that is roughly equal to the known size of an atom $(1 0^{- 10} m)$ .
(a) Construct a quantity with the dimensions of length from the fundamental constants $e, m_{e}, an d c$ . Determine its numerical value.

Question

Classically, an electron can be in any orbit around the nucleus of an atom. Then what determines the typical atomic size? Why is an atom not, say, thousand times bigger than its typical size? The question had greatly puzzled Bohr before he arrived at his famous model of the atom that you have learnt in the text. To simulate what he might well have done before his discovery, let us play as follows with the basic constants of nature and see if we can get a quantity with the dimensions of length that is roughly equal to the known size of an atom

(1 0^{- 10} m)

.

(a) Construct a quantity with the dimensions of length from the fundamental constants

e, m_{e}, an d c

. Determine its numerical value.

Filo · Accepted Answer

According to Coulomb's law, the force between hydrogen nucleus and electron is giben as:

F = \frac{1}{4 π ε _{0}} . \frac{e ^{2}}{r ^{2}}

\Rightarrow r = \frac{1}{4 π ε _{0}} \frac{e ^{2}}{F . r}

Now, using the fundamental constants

e, m_{e}

and

c

, we will obtain a quantity which has the dimensions of length.

We know that

F . r

(force x distance) is the amount work or energy and it is also given as

= m c^{2}

∴ r = \frac{1}{4 π ε _{0}} \frac{e ^{2}}{m c ^{2}} = 2.8 \times 1 0^{- 15} m

.

It is comparatively smaller than the size of the atom.

Question Text	Classically, an electron can be in any orbit around the nucleus of an atom. Then what determines the typical atomic size? Why is an atom not, say, thousand times bigger than its typical size? The question had greatly puzzled Bohr before he arrived at his famous model of the atom that you have learnt in the text. To simulate what he might well have done before his discovery, let us play as follows with the basic constants of nature and see if we can get a quantity with the dimensions of length that is roughly equal to the known size of an atom $(1 0^{- 10} m)$ . (a) Construct a quantity with the dimensions of length from the fundamental constants $e, m_{e}, an d c$ . Determine its numerical value.
Answer Type	Text solution:1
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Text solutionVerified

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