Nuclear binding energy

A nucleus of mass M+ m is at rest and decays into two daughter

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Solving time: 2 mins

A nucleus of mass $M + Δ m$ is at rest and decays into two daughter nuclei of equal mass $M /2$ each. Speed of light is c

The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then,
(a) $E_{2} = 2 E_{1}$
(b) $E_{1} > E_{2}$
(c) $E_{2} > E_{1}$
(d) $E_{1} = 2 E_{2}$

Views: 5,610 students

Updated on: Nov 6, 2023

Book:

Arihant Physics JEE Main Chapterwise Solutions (2019-2002) (Arihant)

Exam:

JEE Mains 2010

Text solutionVerified

E x p . (c)

After decay, the daughter nuclei will be more stable, hence binding energy per nucleon will be more than that of their parent nucleus.

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Evelyn Discussed

A nucleus of mass

M + Δ m

is at rest and decays into two daughter nuclei of equal mass

M /2

each. Speed of light is c

The binding energy per nucleon for the parent nucleus is

E_{1}

and that for the daughter nuclei is

E_{2}

. Then,
(a)

E_{2} = 2 E_{1}

(b)

E_{1} > E_{2}

(c)

E_{2} > E_{1}

(d)

E_{1} = 2 E_{2}

5 mins ago

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5 mins ago

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Question Text	A nucleus of mass $M + Δ m$ is at rest and decays into two daughter nuclei of equal mass $M /2$ each. Speed of light is c The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then, (a) $E_{2} = 2 E_{1}$ (b) $E_{1} > E_{2}$ (c) $E_{2} > E_{1}$ (d) $E_{1} = 2 E_{2}$
Updated On	Nov 6, 2023
Topic	Structure of Atom
Subject	Chemistry
Class	Class 11
Answer Type	Text solution:1 Video solution: 4
Upvotes	511
Avg. Video Duration	6 min

Text solutionVerified

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A nucleus of mass M+Δm is at rest and decays into two daughter nuclei of equal mass M/2 each. Speed of light is cThe binding energy per nucleon for the parent nucleus is E1​ and that for the daughter nuclei is E2​. Then,(a) E2​=2E1​(b) E1​>E2​(c) E2​>E1​(d) E1​=2E2​

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