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Preparation of ether

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New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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(d) Elimination is favoured.
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Practice questions from New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

Question 1
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Select the incorrect alternate.
  1. Methanol is very toxic to humans, leading to blindness and even death
  2. methanol mixture is called rectified spirit
  3. Methanol is used as a premium fuel to power racing car engines
  4. Ethanol is mixed with petroleum products to produce non-lead gasoline for use in internal combustion engine
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Alcohols, Phenols and Ethers

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New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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Question 2
Medium
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Topic

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Alcohols, Phenols and Ethers

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New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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Question 3
Medium
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Use of methanol for "drink" may cause blindness and even death. It is due to
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  2. its reduction to
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  4. its oxidation to
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Alcohols, Phenols and Ethers

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Book:

New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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Question 4
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Alcohols, Phenols and Ethers

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New Pattern JEE Problems Chemistry for JEE Main and Advance( Master Problem Package) (Arihant)

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Practice more questions from Alcohols, Phenols and Ethers

Question 1
Easy
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. This mode of reduction of acid to alcohol can be affected by:
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Alcohols, Phenols and Ethers

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Advance Problem in Organic Chemistry (GRB)

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Question 2
Hard
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Compound is :
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Question 3
Medium
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Product (A) of reaction is:

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  3. Option 3
  4. Option 4
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Alcohols, Phenols and Ethers

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Book:

Advanced Problems in Organic Chemistry for JEE (M.S. Chouhan)

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Question 4
Hard
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Sum of number of alcoholic groups in product and is:
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Alcohols, Phenols and Ethers

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Advanced Problems in Organic Chemistry for JEE (M.S. Chouhan)

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The total number of ions present in an aqueous solution of 1 mole of a complex will be: (complex ionizes in water as
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Question 2
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Center is the stability of the stated ammonium calon stringer should be the corresponding imine on a hone. Thus, the order of try if aliphatte amies should be primary aindary tertiary which in opposite in the todoctive effect based order Secondly, when the CH there is no sterte indraser to alkyl group is small ke be sterte hirderance to H feiding. Therefore, the change of nature of 11-bonding In case the alkyl grop is hier than CH, group, there will the alloyl group eat from it, in CH, reeds in change of the onder of basic strength Thus, there is a subtle interplay of the indiv effect, solvation effect and steric funderance of the alleyl group which decides the basic strength of alkyl amines in the aqueos state The order of baste strength in case of methyl substituted amnes and ey substituted amines in aqueous solution is as followe (C HỘNH: KIMONG CỤMÌNH, NH, KHÍNH CHÍNH, KHÔNG SINH, (b) Arylamines versus ammonia pk, value of aniline is quite high. Why is it so it is because in aniline or other arylamines, the NH, group is attached directly to the benzene ring. It results in the unshared electron pair on nitroen atom to be in conjugation with the benzene ring and thus making it less available for protonation. If you write different resonating structures of aniline, you will find that andline is a resonance hybrid of the following five structures. NH, S 1 NH ← NH. III NH. IV 1 On the other hand, anilinium ion obtained by accepting a proton can have only two resonating structures (kekule). NH, NH, 1) NH, (2) V 1 11 We know that greater the number of resonating structures, greater is the stability. Thus you can infer that aniline (five resonating structures) is more stable than anilinium ion. Hence, the proton acceptability or the basic nature of aniline or other aromatic amines would be less than that of ammonia. In case of substituted aniline, it is observed that electron releasing groups like -OCH,. -CH, Increase basic strength whereas electron withdrawing groups like -NO,. -SOH. -COOH. -X decrease it. 399, Amitnes coordination niodes Amines 10) Hoff
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Question 3
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Suppose that the Pauli exclusion principle were "No more than two electrons can have the same four quantum numbers." What would be the electron configurations of the ground states for the first six elements of the periodic table, assuming that, except for the Pauli principle, the usual building-up principle held?
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awes Find whether, or a is a stroun orldisiug eyent stroung
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Question Text
TopicAlcohols, Phenols and Ethers
SubjectChemistry
ClassClass 12
Answer TypeText solution:1
Upvotes125