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Question

Phase of shortest duration is

A
Prophase

B
Metaphase

C
Anaphase

D
S-phase

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Text SolutionText solutionverified iconVerified

Mitosis consists of four basic phases: prophase, metaphase, anaphase, and telophase.  These phases occur in this strict sequential order, and cytokinesis - the process of dividing the cell contents to make two new cells - starts in anaphase or telophase.
1. Prophase - During prophase, chromosomes get visible (chromatids), the centrioles migrate to the poles, nuclear membrane and nucleolus disappear and spindle formation is seen. Cells spend 14 % of the cell cycle in this phase
which is the next largest amount of time spent in a phase after interphase. 
2. Metaphase - During this, chromosomes lineup around the centre (Cells in metaphase have the chromosomes, which appear as long thin strands under the microscope). Metaphase takes about 4 percent of the time required for the completion of a cell cycle.
3. Anaphase - here, chromatids separate and move to opposite poles by spindle fibers. This allows each daughter cell to have an identical copy of each of the original cell’s chromosomes. This phase only takes about 0.8 percent of the cell cycle to complete, which is the shortest time required out of all the phases.
4. Telophase - During this phase, chromosomes disappear (become chromatin), nuclear membrane reforms, nucleoli reappears, spindle disappears and centrioles duplicate. Telophase takes up about 3 percent of the cell cycle. 
Hence, the correct answer is option C.
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Question Text
Phase of shortest duration is
Answer TypeText solution:1
Upvotes150