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A system has 50 pascal of osmotic pressure and its turgor pressure is zero. Now due to entry of some water osmotic pressure decreases by 10 pascal then what will be the change in DPD of this system?
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Water moves from an area of lower diffusion pressure deficit (DPD) to an area of higher DPD. The value of DPD is calculated as the algebraic difference between osmotic pressure and turgor pressure. In a flaccid cell, the turgor pressure is zero and hence DPD will be equal to the osmotic pressure. As water enters a cell, there is an increase in turgor pressure, as the solution in cell sap turns less concentrated there is a fall in osmotic pressure and consequently the DPD falls. In a fully turgid cell, the value of DPD is equal to zero and turgor pressure is numerically equal to osmotic pressure.
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Question Text | A system has 50 pascal of osmotic pressure and its turgor pressure is zero. Now due to entry of some water osmotic pressure decreases by 10 pascal then what will be the change in DPD of this system? |
Updated On | Mar 31, 2023 |
Topic | Transport in Plants |
Subject | Biology |
Class | Class 11 |
Answer Type | Text solution:1 Video solution: 3 |
Upvotes | 411 |
Avg. Video Duration | 4 min |