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Also {E O}=-{B C}=-({b}-{a})={a}-{b} Illustration 9. The figur

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Also $EO = - BC = - (b - a) = a - b$ Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that $ab + a c + a d + a θ + a f = 6 a o$ Solution. Applying parallelogram law of vectors to the parallelogram abof,

Name: Video solution 1: Also EO=−BC=−(b−a)=a−b Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that ab+ac+ad+aθ+af=6ao Solution. Applying parallelogram law of vectors to the parallelogram abof,
Uploaded: 2022-10-19T05:47:51.000Z
Duration: 5 min
Description: Video solution 1: Also EO=−BC=−(b−a)=a−b Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that ab+ac+ad+aθ+af=6ao Solution. Applying parallelogram law of vectors to the parallelogram abof,

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Updated on: Oct 19, 2022

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EO = - BC = - (b - a) = a - b

Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that

ab + a c + a d + a θ + a f = 6 a o

Solution. Applying parallelogram law of vectors to the parallelogram abof,

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Question Text	Also $EO = - BC = - (b - a) = a - b$ Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that $ab + a c + a d + a θ + a f = 6 a o$ Solution. Applying parallelogram law of vectors to the parallelogram abof,
Updated On	Oct 19, 2022
Topic	Modern Physics
Subject	Physics
Class	Class 11
Answer Type	Video solution: 1
Upvotes	141
Avg. Video Duration	5 min

Also $EO = - BC = - (b - a) = a - b$ Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that $ab + a c + a d + a θ + a f = 6 a o$ Solution. Applying parallelogram law of vectors to the parallelogram abof,

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Also EO=−BC=−(b−a)=a−b Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that ab+ac+ad+aθ+af​=6ao Solution. Applying parallelogram law of vectors to the parallelogram abof,

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Also $EO = - BC = - (b - a) = a - b$ Illustration 9. The figure shows a regular hexagon abcdef with o as centre. Prove that $ab + a c + a d + a θ + a f = 6 a o$ Solution. Applying parallelogram law of vectors to the parallelogram abof,