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Problem 7.18 Consider a 45T laminate. Each lamina is 2.5 mm thick. The material properties are: E1 = 204.6 GPa E2 = 20.46 GPa G12 = 6.89 GPa V12 = 0.3 F1t = 826.8 MPa F1c = 482.3 MPa F2t = F2c = 68.9 MPa F6 = 241.15 MPa Determine the value of the forces Nx, Ny, Nxy, Mx, My, Mxy required to produce a curvature Kx = 0.00545 mm^-1 and Ky = 0.00486 mm^-1. Neglect small numbers and shear deformation.
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Question Text | Problem 7.18
Consider a 45T laminate. Each lamina is 2.5 mm thick. The material properties are:
E1 = 204.6 GPa
E2 = 20.46 GPa
G12 = 6.89 GPa
V12 = 0.3
F1t = 826.8 MPa
F1c = 482.3 MPa
F2t = F2c = 68.9 MPa
F6 = 241.15 MPa
Determine the value of the forces Nx, Ny, Nxy, Mx, My, Mxy required to produce a curvature Kx = 0.00545 mm^-1 and Ky = 0.00486 mm^-1. Neglect small numbers and shear deformation. |
Topic | All topics |
Subject | Physics |
Class | Class 12 |