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A beam of light consisting of two wavelengths 6500 and 5200

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A beam of light consisting of two wavelengths $6500 \overset{˚}{A}$ and $5200 \overset{˚}{A}$ is used to obtain interference fringes in an Young's double slit experiment. What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ? Given the distance between the slits in $2 mm$ and the distance of the screen from the slits is $1.2 m$ .

Name: Video solution 1: A beam of light consisting of two wavelengths 6500A˚ and 5200A˚ is used to obtain interference fringes in an Young's double slit experiment. What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ? Given the distance between the slits in 2 mm and the distance of the screen from the slits is 1.2 m.
Uploaded: 2023-03-19T18:01:47.000Z
Duration: 7 min
Description: Video solution 1: A beam of light consisting of two wavelengths 6500A˚ and 5200A˚ is used to obtain interference fringes in an Young's double slit experiment. What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ? Given the distance between the slits in 2 mm and the distance of the screen from the slits is 1.2 m.

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Updated on: Mar 19, 2023

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Harper Discussed

A beam of light consisting of two wavelengths

6500 \overset{˚}{A}

and

5200 \overset{˚}{A}

is used to obtain interference fringes in an Young's double slit experiment. What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ? Given the distance between the slits in

2 mm

and the distance of the screen from the slits is

1.2 m

11 mins ago

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Uploaded on: 3/19/2023

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Question Text	A beam of light consisting of two wavelengths $6500 \overset{˚}{A}$ and $5200 \overset{˚}{A}$ is used to obtain interference fringes in an Young's double slit experiment. What is the least distance from the central maximum where the bright fringes due to both the wavelengths coincide ? Given the distance between the slits in $2 mm$ and the distance of the screen from the slits is $1.2 m$ .
Updated On	Mar 19, 2023
Topic	Optics
Subject	Physics
Class	Class 12
Answer Type	Video solution: 1
Upvotes	105
Avg. Video Duration	7 min

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