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q=m c \Delta T \quad \text { specific heat of water }=1.0 \mathrm{cal} / \mathrm{g}{ }^{\circ} \mathrm{C} \text { or } 4.18 \mathrm{~J} / \mathrm{g}{ }^{\circ} \mathrm{C} \\
- q=m \Delta H \\
- \text { _ } \\
- \end{array}
- How much heat (in calories) is released if of water is cooled from to ?
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Question Text | q=m c \Delta T \quad \text { specific heat of water }=1.0 \mathrm{cal} / \mathrm{g}{ }^{\circ} \mathrm{C} \text { or } 4.18 \mathrm{~J} / \mathrm{g}{ }^{\circ} \mathrm{C} \\ |
Topic | All topics |
Subject | Chemistry |
Class | High School |