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molality ={ { moles } 1000}{W(g) { of solvent }} - It does n

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molality $= \frac{moles \times 1000}{W ( g ) of solvent}$ - It does not change on changing temperature. Example 2: If $20 ml$ of $0.5 M Na_{2} SO_{4}$ is mixed with $50 ml$ of $0.2 MH_{2} SO_{4} &30 ml$ of $0.4 MAl_{2} (SO_{4})_{3}$ solution. Calculate $[Na^{+}]$ , $[H^{+}], [SO_{4}^{2 -}], [Al^{3 +}]$ . [Assuming $100%$ dissociation]

Name: Video solution 1: molality =W(g) of solvent moles ×1000 - It does not change on changing temperature. Example 2: If 20ml of 0.5MNa2SO4 is mixed with 50ml of 0.2MH2SO4&30ml of 0.4MAl2(SO4)3 solution. Calculate [Na+], [H+],[SO42−],[Al3+]. [Assuming 100% dissociation]
Uploaded: 2023-05-29T16:48:32.000Z
Duration: 2 min
Description: Video solution 1: molality =W(g) of solvent moles ×1000 - It does not change on changing temperature. Example 2: If 20ml of 0.5MNa2SO4 is mixed with 50ml of 0.2MH2SO4&30ml of 0.4MAl2(SO4)3 solution. Calculate [Na+], [H+],[SO42−],[Al3+]. [Assuming 100% dissociation]

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Updated on: May 29, 2023

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Evelyn Discussed

molality

= \frac{moles \times 1000}{W ( g ) of solvent}

- It does not change on changing temperature. Example 2: If

20 ml

0.5 M Na_{2} SO_{4}

is mixed with

50 ml

0.2 MH_{2} SO_{4} &30 ml

0.4 MAl_{2} (SO_{4})_{3}

solution. Calculate

[Na^{+}]

[H^{+}], [SO_{4}^{2 -}], [Al^{3 +}]

. [Assuming

100%

dissociation]

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Question Text	molality $= \frac{moles \times 1000}{W ( g ) of solvent}$ - It does not change on changing temperature. Example 2: If $20 ml$ of $0.5 M Na_{2} SO_{4}$ is mixed with $50 ml$ of $0.2 MH_{2} SO_{4} &30 ml$ of $0.4 MAl_{2} (SO_{4})_{3}$ solution. Calculate $[Na^{+}]$ , $[H^{+}], [SO_{4}^{2 -}], [Al^{3 +}]$ . [Assuming $100%$ dissociation]
Updated On	May 29, 2023
Topic	Gases & Solutions
Subject	Chemistry
Class	Class 11
Answer Type	Video solution: 1
Upvotes	72
Avg. Video Duration	2 min

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molality =W(g) of solvent moles ×1000​ - It does not change on changing temperature. Example 2: If 20ml of 0.5MNa2​SO4​ is mixed with 50ml of 0.2MH2​SO4​&30ml of 0.4MAl2​(SO4​)3​ solution. Calculate [Na+], [H+],[SO42−​],[Al3+]. [Assuming 100% dissociation]

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