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Change in volume has to be calculated if one mole of graphite is converted into diamond.

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[{'sectionSequence': 0, 'sectionHeaderText': '', 'solutionSubsections': [{'sectionName': 'Interpretation Introduction', 'sectionText': '\r\n

Interpretation:

\r\n

Change in volume has to be calculated if one mole of graphite is converted into diamond.

\r\n', 'sectionSequence': 0, 'computed': {'sectionNameWithHtmlRemoved': 'Interpretation Introduction', 'sectionTextWithHtmlRemoved': 'Interpretation: Change in volume has to be calculated if one mole of graphite is converted into diamond.'}}, {'sectionName': 'Explanation', 'sectionText': '\r\n

Graphite and diamond are two allotropes of carbon. In one mole of carbon atom there are 12.01\u2009g of carbon.

\r\n

Volume of graphite:

\r\n

Volume of graphite can be calculated using the density of graphite and mass of one mole of graphite as follows;

\r\n

Volume\u2009of\u2009Graphite=MassDensity=12.01\u2009g2.26\u2009g/cm3=5.31\u2009cm3

\r\n

Volume of diamond:

\r\n

Volume of diamond can be calculated using the density of diamond and mass of one mole of diamond as follows;

\r\n

Volume\u2009of\u2009Diamond=MassDensity=12.01\u2009g3

', 'sectionSequence': 2, 'computed': {'sectionNameWithHtmlRemoved': 'Explanation', 'sectionTextWithHtmlRemoved': 'Graphite and diamond are two allotropes of carbon. In one mole of carbon atom there are 12 .01 g of carbon. Volume of graphite: Volume of graphite can be calculated using the density of graphite and mass of one mole of graphite as follows; Volume of Graphite = Mass Density = 12 .01 g 2 .26 g/cm 3 = 5.31 cm 3 Volume of diamond: Volume of diamond can be calculated using the density of diamond and mass of one mole of diamond as follows; Volume of Diamond = Mass Density = 12 .01 g 3'}}]}]
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Question Text
Change in volume has to be calculated if one mole of graphite is converted into diamond.
TopicAll topics
SubjectChemistry
ClassClass 12
Answer TypeText solution:1