A parent having autosomal dominant disease then what will be the probability of diseased offspring irrespective of sex of the child?a. $90\%$ b. $10\%$ c. $50\%$ d. $100\%$

Sure, here are the step-by-step solutions with LaTeX tags: 1. Identify the problem: $\frac{1}{x+3}+\frac{1}{x-3}=\frac{2}{x^2-9}$ 2. Find a common denominator for all fractions: $\frac{(x-3)+(x+3)}{(x+3)(x-3)}=\frac{2}{(x+3)(x-3)}$ 3. Simplify the fractions on the left side of the equation: $\frac{2x}{(x+3)(x-3)}=\frac{2}{(x+3)(x-3)}$ 4. Cancel out the common factor of 2 on both sides of the equation: $\frac{x}{(x+3)(x-3)}=\frac{1}{(x+3)(x-3)}$ 5. Multiply both sides of the equation by the common denominator: $x=1$ 6. Check the solution by plugging it back into the original equation: $\frac{1}{1+3}+\frac{1}{1-3}=\frac{2}{1^2-9}$$\frac{1}{4}-\frac{1}{2}=\frac{2}{-8}$$-\frac{1}{4}=-\frac{1}{4}$ 7. Therefore, the solution is $x=1$.